Why does plastic container slides off at the same speed?

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SUMMARY

The discussion centers on the behavior of two cylindrical plastic containers on a turntable, specifically why both containers slide off at the same speed despite differing masses. The key conclusion is that the mass does not affect the sliding speed due to the relationship between static friction and centripetal force. The relevant equations include F = ma and Us * Fn < mv^2 / r, leading to the simplified equation Us * g = v^2 / r, which demonstrates that the mass cancels out in the context of circular motion.

PREREQUISITES
  • Understanding of circular motion and centripetal force
  • Knowledge of static friction and its coefficient (Us)
  • Familiarity with Newton's second law (F = ma)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the principles of centripetal acceleration and its dependence on radius and velocity
  • Explore the concept of static friction and its role in circular motion
  • Learn how to derive equations of motion for objects in circular paths
  • Investigate real-world applications of friction in rotational systems
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone interested in understanding the dynamics of circular motion and frictional forces.

gijungkim
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Homework Statement


Two small cylindrical plastic containers with flat bottoms are placed on a turntable that has a smooth flat surface. Canister A is empty; canister B contains lead shot. Each canister is the same distance r from the center. The coefficient of static friction between the canisters and the turntable is Us . When the speed of the turntable is gradually increased,

a. only the lighter container slides outward off the turntable; the heavier one stays on.

b. only the heavier container slides outward off the turntable; the lighter one stays on.

c. both containers slide off the turntable at the same turntable speed.

d. the lighter container slides inward.

e. the heavier container slides inward.

Homework Equations

The Attempt at a Solution



The answer is c, but I don't understand why. Can anyone explain it with equations??
 
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gijungkim said:

Homework Statement


Two small cylindrical plastic containers with flat bottoms are placed on a turntable that has a smooth flat surface. Canister A is empty; canister B contains lead shot. Each canister is the same distance r from the center. The coefficient of static friction between the canisters and the turntable is Us . When the speed of the turntable is gradually increased,

a. only the lighter container slides outward off the turntable; the heavier one stays on.

b. only the heavier container slides outward off the turntable; the lighter one stays on.

c. both containers slide off the turntable at the same turntable speed.

d. the lighter container slides inward.

e. the heavier container slides inward.

Homework Equations

The Attempt at a Solution



The answer is c, but I don't understand why. Can anyone explain it with equations??
Initially, the two containers follow the turntable, correct?

That means that they are undergoing circular motion, which is an acceleration, correct?

The only way that this can happen is if there is a centripetal force pushing in.

What is the force for the two canisters? F= ma. a = v^2/r

The cans fall off when the frictional force becomes less than the centripetal force.

Write two equations for the two cans, and see how the two velocities compare to each other.
 
Quantum Defect said:
Initially, the two containers follow the turntable, correct?

That means that they are undergoing circular motion, which is an acceleration, correct?

The only way that this can happen is if there is a centripetal force pushing in.

What is the force for the two canisters? F= ma. a = v^2/r

The cans fall off when the frictional force becomes less than the centripetal force.

Write two equations for the two cans, and see how the two velocities compare to each other.
so Us*Fn < mv^2 / r this is when the container slides off right? And if I simplify this equation, I get Us * g = v^2 / r. Since there is no m in this equation, mass doesn't matter right? I don't know if I did it right or not haha
 
gijungkim said:
so Us*Fn < mv^2 / r this is when the container slides off right? And if I simplify this equation, I get Us * g = v^2 / r. Since there is no m in this equation, mass doesn't matter right? I don't know if I did it right or not haha

Sure it's right. The mass doesn't matter. The 'centripetal force' is proportional to mass and so is the normal force.
 
Dick said:
Sure it's right. The mass doesn't matter. The 'centripetal force' is proportional to mass and so is the normal force.
Thank you! :)
 

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