A mass m = 71 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R = 16.1 m and finally a flat straight section at the same height as the center of the loop (16.1 m off the ground). Since the mass would not make it around the loop if released from the height of the top of the loop (do you know why?) it must be released above the top of the loop-the-loop height. (Assume the mass never leaves the smooth track at any point on its path.)
In the problem, I've already found:
What is the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track? 12.561
What height above the ground must the mass begin to make it around the loop-the-loop? 40.25
I'm stuck on the next few parts which are
a. If the mass has just enough speed to make it around the loop without leaving the track, what will its speed be at the bottom of the loop?
b. If the mass has just enough speed to make it around the loop without leaving the track, what is its speed at the final flat level (16.1 m off the ground)?
c. Now a spring with spring constant k = 15400 N/m is used on the final flat surface to stop the mass. How far does the spring compress?
d. It turns out the engineers designing the loop-the-loop didn’t really know physics – when they made the ride, the first drop was only as high as the top of the loop-the-loop. To account for the mistake, they decided to give the mass an initial velocity right at the beginning.
How fast do they need to push the mass at the beginning (now at a height equal to the top of the loop-the-loop) to get the mass around the loop-the-loop without falling off the track?
e. The work done by the normal force on the mass (during the initial fall) is: Positive, Negative, or Zero.
F=MA and F=mv^2/r
The Attempt at a Solution
a. I think it is the same speed I found before, (12.561), but I'm not sure.
b. I thought I had to use .5mv^2=.5m1v^2+ghm, but that makes the velocity negative, so I don't think that can be right.
c. I need the velocity from part b to do this one.
d. I don't even know where to start on this one.
e. I think it's zero, because the normal force didn't really do anything, only gravity did, but I don't know if this is right.