Why does refractive index reverse for light returning through a spherical surface?

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stpmmaths
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Homework Statement



Worked solution to Example 10.9 on refraction through a glass sphere, showing a ray diagram with a distant object, first and second refracting surfaces, and the refractive index equations applied at each surface.


Homework Equations





The Attempt at a Solution



I was kind of confuse with the use of refractive index.

For the first part of question, n1 = 1.00 and n2 = 1.50. From what I know, the object is at vacuum so the n1 = 1.00.

But why for the second part of the question, n1 = 1.50 and n2 = 1.00 ? After the first refracting surface, the image should be at the vacuum too. But why we use n1 = 1.50?
 
Attachments
  • Worked solution to Example 10.9 on refraction through a glass sphere, showing a ray diagram with X, C, Y and Z points and the first and second refracting surfaces, with equations for each surface.
    IMG.jpg
    45 KB · Views: 926
Welcome to PF!

Hi stpmmaths! Welcome to PF! :smile:
stpmmaths said:
I was kind of confuse with the use of refractive index.

For the first part of question, n1 = 1.00 and n2 = 1.50. From what I know, the object is at vacuum so the n1 = 1.00.

But why for the second part of the question, n1 = 1.50 and n2 = 1.00 ? After the first refracting surface, the image should be at the vacuum too. But why we use n1 = 1.50?

(I can't see your attachment yet, but …)

I assume that the light starts by going into the sphere from the air (or vacuum), so it's going from n = 1 to n = 1.5;

then it travels through the sphere (n = 1.5) until it hits the opposite surface and comes out again, so it's going from n = 1.5 to n = 1. :wink:
 
tiny-tim said:
Hi stpmmaths! Welcome to PF! :smile:(I can't see your attachment yet, but …)

I assume that the light starts by going into the sphere from the air (or vacuum), so it's going from n = 1 to n = 1.5;

then it travels through the sphere (n = 1.5) until it hits the opposite surface and comes out again, so it's going from n = 1.5 to n = 1. :wink:

Ok..I understand a bit.

Now I came across with another question similar to this question(quite similar)

Quenstion:
Textbook problem diagram of a glass sphere with a coin labelled O on its left surface, centre C, and an eye on the right looking along a dashed diameter through the sphere to point X.

Answer:
Ray diagram of a glass sphere with centre C and a refractive surface at its upper right, showing an object I on the left, point O on the sphere, point X, the eye on the right, and a 12 cm diameter, followed by worked refraction equations below.


Why the n1 is 1.50 if we say the light starts from vacuum?:confused:
 
Attachments
  • Textbook problem diagram of a glass sphere with a coin at point O on its left surface, centre C, and an eye at right viewing along the diameter through point X on the far side.
    IMG_0001.jpg
    30.5 KB · Views: 487
  • Ray diagram of a glass sphere with a refractive surface, object I on the left, centre C, point O, point X, eye on the right, and a 12 cm diameter, followed by worked refraction calculation with u = +12 cm, r = +6 cm, n1 = 1.50, n2 = 1.00, giving v = -23.8 cm.
    IMG_0002.jpg
    33.1 KB · Views: 617
stpmmaths said:
Why the n1 is 1.50 if we say the light starts from vacuum?:confused:

Because the light starts from the coin, inside the sphere, not from vacuum. :wink:
 
stpmmaths said:
Why the n1 is 1.50 if we say the light starts from vacuum?:confused:

Look carefully at the arrows in the figure. Where do they start from?

EDIT: to clarify, look at the interface where the two rays meet. The ray arrows indicate they go from the glass into the air.

p.s. Hello tiny-tim!