Why Does the Constant Rank Theorem Hold True?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 reply · 6K views
center o bass
Messages
545
Reaction score
2
There are two theorems from multivariable calculus that is very important for manifold theory.
The first is the inverse function theorem and the second is the "constant rank theorem". The latter states that

(Constant rank theorem). If ##f : U\subset \mathbb{R}^n \to \mathbb{R}^m## has constant rank ##k## in a neighborhood of a point ##p \in U## , then after a suitable change of coordinates near ##p## in ##U## and ##f(p)## in ##\mathbb{R}^m##, the map ##f## assumes the form ##(x^1,...,x^n)\mapsto (x^1,...,x^k,0,...,0)##.
More precisely, there are a diffeomorphism ##G## of a neighborhood of ##p## in ##U## sending ##p## to the origin in ##\mathbb{R}^n## and a diffeomorphism ##F## of a neighborhood of ##f(p)## in ##\mathbb{R}^m## sending ##f(p)## to the origin in ##\mathbb{R}^m## such that ##(F ◦ f ◦ G)^{−1}(x^1,...,x^n) = (x^1,...,x^k,0,...,0).##

I've gone through the proof of the theorem, but I'm left with little intuition on why it has to be true. Therefore I wonder, do you have any intuitive explanation of why the theorem has to be true?
 
Physics news on Phys.org