Why Does the Green Curve Have Higher Probability at the Left of the Barrier?

Click For Summary
SUMMARY

The discussion centers on the numerical plotting of probability distributions for a particle encountering a barrier, specifically focusing on the behavior of the green curve (n=1) which shows higher probability on the left side of the barrier. The user initially questions the results, seeking clarification on the implications of a particle approaching from the right. It is concluded that the observed distribution aligns with the expected behavior of energy eigenfunctions, which are symmetric or antisymmetric around the center when infinite barriers are present.

PREREQUISITES
  • Understanding of quantum mechanics and wave functions
  • Familiarity with potential barriers in quantum systems
  • Knowledge of energy eigenfunctions and their properties
  • Experience with numerical methods for plotting probability distributions
NEXT STEPS
  • Study quantum mechanics concepts related to potential barriers and wave functions
  • Learn about energy eigenfunctions and their symmetry properties
  • Explore numerical methods for simulating quantum systems
  • Investigate the implications of boundary conditions on probability distributions
USEFUL FOR

Students and researchers in quantum mechanics, physicists analyzing particle behavior in potential fields, and anyone interested in the numerical simulation of quantum systems.

Black Integra
Messages
56
Reaction score
0
Hello people, I'm trying to plot probability distributions from the given potential numerically.
These are the results (particle coming from the right)

https://fbcdn-sphotos-g-a.akamaihd.net/hphotos-ak-prn1/s720x720/546478_516459578368236_1799346634_n.jpg

What I want to know is why does the green curves (n=1) have higher probability at the left of the barrier? Why not the right(as the other curves)?

Or if my results are completely wrong?

Can anybody analyze my results, please...
 
Physics news on Phys.org
What do you mean by "particle coming from the right"? If you have infinite barriers on both the left and the right, then you are presumably calculating the energy eigenfunctions, and these should be either symmetric or antisymmetric about the center.
 
sorry for the question, I have found my fault.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
Replies
6
Views
6K
  • · Replies 19 ·
Replies
19
Views
5K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K