Why does the ring homomorphism proof introduce f(x) when the theorem doesn't mention it?

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Artusartos
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I attached a page from my textbook, because there was something that I didn't understand.

What I don't understand is in the proof it says let f(x) be...etc. but in the theorem, it says nothing about f(x). In other words, where in the thoerem does it say anything about f(x). Why are they talking about f(x) in the proof?

Thanks in advance
 
Attachments
  • Photo of a textbook page showing Theorem 2.25 on ring homomorphisms and its proof by induction, including the definition of the map Phi from R[x] to S and a partial verification that Phi preserves addition.
    20121224_221945.jpg
    29.4 KB · Views: 472
  • Photo of a printed textbook page showing a proof that a map Phi from polynomial rings is a ring homomorphism, with sums, the product f(x)g(x), and the uniqueness argument.
    20121224_222018.jpg
    34.7 KB · Views: 459
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Notice that f(x) is just a polynomial in R[x] and the author(s) use it to define the map claimed in the proposition.