Why Does This Probability Equation Evaluate to 0.5?

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SUMMARY

The probability equation \(\frac{2^{f(n)+2}}{2^{f(n)+1}} = \frac{1}{2}\) evaluates to 0.5 due to the simplification of the terms involved. Specifically, the equation simplifies to \(\frac{2 \times 2^{f(n)+1}}{2^{f(n)+1}} = 2\), indicating a misunderstanding of the original expression. The context provided clarifies that there are \(2^{f(n)+2}\) texts, and the probability of selecting a related compressed text of length ≤ f(n) is indeed less than \(\frac{2^{f(n)+2}}{2^{f(n)+1}}\), confirming the evaluation to 0.5 is accurate when the equation is correctly interpreted.

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tntcoder
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Hi,

Please can someone explain to me how this probability equation evaluates to 0.5

[tex]\frac{2^{f(n)+2}}{2^{f(n)+1}} = \frac{1}{2}[/tex]

f(n) is essentially anything in this context.

For me the probability evaluates to 2, but this is straight out a research paper and I can't doubt their maths.

This is the context:

Because there are [tex]2^{f(n)+2}[/tex] texts with length [tex]f(n)+2[/tex], the probability for a selected text with length [tex]f(n)+2[/tex] having a related
compressed text of length ≤ f(n) is less than [tex]\frac{2^{f(n)+2}}{2^{f(n)+1}} = \frac{1}{2}[/tex]

Please can someone explain to me where the 0.5 comes from? I can see if i turn the equation upside down it works, but I am guessing its not that simple :p
 
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Make sure you've typed things correctly - otherwise the expression seems to be the reciprocal of what it should be.

[tex] \frac{2^{f(n)+2}}{2^{f(n)+1}} = \frac{2 \times 2^{f(n)+1}}{2^{f(n)+1}} = 2[/tex]

If the original expression is the reciprocal of what you've typed, the expression does
reduce to 1/2
 

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