Why Does XRD Show Amorphous Spectrum in Crystalline Hydroxyapatite Nanopowder?

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SUMMARY

The discussion focuses on the interpretation of X-ray diffraction (XRD) data from crystalline hydroxyapatite nanopowder, which unexpectedly shows an amorphous spectrum. The broadening effect of small crystal size on the Debye rings is highlighted, with the relationship defined by the equation B=0.9λ/tcos(θ). It is emphasized that the peak broadening due to grain size must be corrected using a large-grained standard of the same material. For further understanding, the reference "Elements of X-Ray Diffraction, 2nd Edition" by B.D. Cullity is recommended.

PREREQUISITES
  • X-ray diffraction (XRD) principles
  • Understanding of Debye rings
  • Knowledge of crystal size measurement techniques
  • Familiarity with peak broadening calculations
NEXT STEPS
  • Study the equation B=0.9λ/tcos(θ) in detail
  • Learn about peak broadening corrections in XRD analysis
  • Research the influence of crystal size on diffraction patterns
  • Read "Elements of X-Ray Diffraction, 2nd Edition" by B.D. Cullity
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Researchers and scientists in materials science, particularly those working with hydroxyapatite and X-ray diffraction analysis, will benefit from this discussion.

Msl
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Hello!

I would like to ask your help in the interpretation of Xrd data from hydroxyapatite nanopowder.
I know from the start that powders which I am analysing are already crystalline (another techniques were used to confirme that) but I keep having a characteristic spectrum of amorphous hydroxyapatite.
Why does this happen? What´s the influence of crystal size during in XRD procedure?

Thank you !
 
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Hello,
A small crystal size will induce a broadening effect of the Debye rings. This relationship is discribed by:

B=0.9\lambda/tcos(\theta)

B = broadening of diffraction line measure at FWHM
t = crystal size diameter

B is the broadening of the peak due to grain size alone, therefore you must correct for the specific machine, do this using a large grained standard (of the same material).

B2 = BM2 - Bs2
Where BM is the measured breadth of the diffraction line and Bs is the measured breadth of the of the standard line.

I hope this helps, all this info can be found with much better explanation in:

Elements of X-Ray Diffraction, 2nd Edition, B.D. Cullity
 

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