Why Don't We Consider the Distance to the Earth's Center for Potential Energy?

Click For Summary

Homework Help Overview

The discussion revolves around the concept of gravitational potential energy, specifically questioning why the distance to the Earth's center is not considered when calculating potential energy for a mass above the ground. The original poster presents a scenario involving a 3kg mass positioned 1m above the floor, seeking clarification on the relevance of the chosen zero point for potential energy.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the idea that gravitational potential energy is relative and question the significance of the zero line. There is a discussion about whether only differences in potential energy matter and how this relates to the concept of absolute potential energy.

Discussion Status

Some participants have provided insights into the nature of gravitational potential energy, noting that it is defined relative to a reference point. The conversation includes an acknowledgment of the approximation used near the Earth's surface and the implications of choosing different reference points for potential energy calculations.

Contextual Notes

There is an ongoing examination of the assumptions behind potential energy calculations, including the implications of using a zero line and the approximation of constant gravitational force near the Earth's surface. The discussion also touches on the relationship between kinetic energy and reference frames, indicating a broader exploration of energy concepts.

Karol
Messages
1,380
Reaction score
22

Homework Statement


A mass of 3kg is 1m above the floor. the zero of the potential energy is chosen to be on the floor.
I understand that the 30j potential energy belongs to both the Earth and the mass, so, why don't i take into account also the distance to the center of the earth?
Why don't i take the distance to the center of the Earth as the potential energy? why is h1 better than h2 (see drawing)?
What does the zero line mean?

Homework Equations


##E_P=mgh##

The Attempt at a Solution


Is it related to the fact that only differences in potential energy count?
 

Attachments

  • Snap1.jpg
    Snap1.jpg
    4.7 KB · Views: 413
Physics news on Phys.org
Karol said:
Is it related to the fact that only differences in potential energy count?

Yes, exactly.

There isn't any 'absolute gravitational potential energy'

It only makes sense to speak of gravitational potential energy relative to some other position.

The "zero line" is just the "some other position" (which we are measuring relative to)

h1 is arbitrary.

(I find it analogous to how kinetic energy only makes sense when measured relative to some other speed.)
 
The potential energy of a mass m that belongs to the gravitational force of the Earth is -GmM/r where G is the gravitational constant, M is the mass of the Earth and r is the distance from the Earth centre if r≥R, the radius of the Earth. In that case, the zero of the potential energy is at infinity.

Very near to the Earth surface, the change of the potential energy can be taken proportional to the change of height. It is an approximation, assuming constant gravitational force. The potential energy with respect to a chosen "ground" is U=mgh. But that is true only for distances which are much shorter than the radius of Earth.

ehild
 
Last edited:
Reply to Nathanel: i thought kinetic energy is fixed, has a meaning, i never learned that kinetic energy is relative to something, i am always asked "what is the kinetic energy of..."
Of course difference in kinetic energy means the energy is transferred elsewhere, but there is also meaning to absolute kinetic energy, no? because the momentum is related to kinetic energy and it's absolute.
I can also be asked what work will a mass of certain speed do and i use kinetic energy to answer
 
The kinetic energy of a particle depends on the frame of reference. If a particle moves with velocity v in a system traveling with velocity V, in the moving frame of reference its kinetic energy is 1/2 mv2, but in the rest frame of reference the veleocity is v+V and the kinetic energy is 1/2 (v+V)2.

ehild
 
  • Like
Likes   Reactions: 1 person

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
14K
Replies
29
Views
3K
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K