Why e-Integral Factor Omits Constant Integral?

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SUMMARY

The discussion centers on the omission of a constant integral when using the integrating factor method for solving linear differential equations, specifically with the exponential integral factor \( e^{\int p(x) dx} \). It highlights that while an arbitrary additive constant can be included in the integral, it does not affect the final solution due to the multiplicative nature of the integrating factor \( \mu \). The example referenced from Wikipedia illustrates that the parameter \( C \) in the solution allows for the redefinition of \( \mu \) without impacting the correctness of the solution.

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bennyska
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whenever i see that integrating factor for solving a linear differential equation with
eint. p(x) dx and then multiplied out in the equation, there seems to be no constant. i tried solving an equation with it the other day, and got an incorrect solution because of it (i think. at least i got a correct solution when i neglected it).
why is this?
 
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Check this example:

http://en.wikipedia.org/wiki/Examples_of_differential_equations

The section "Non-separable first-order linear ordinary differential equations". An arbitrary additive term in the integral in the exponential, can be written as a constant prefactor on [tex]\mu[/tex]. Since the whole equation is multiplied by [tex]\mu[/tex], this is irrelevant for finding the solution.

And you can se in the explicit expression for the final solution y that you have the freedom to redefine [tex]\mu[/tex] by multiplying it ba any nonzero number, since the parameter C is not determined.

Torquil
 


cool, thanks.
 

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