Why e-Integral Factor Omits Constant Integral?

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bennyska
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whenever i see that integrating factor for solving a linear differential equation with
eint. p(x) dx and then multiplied out in the equation, there seems to be no constant. i tried solving an equation with it the other day, and got an incorrect solution because of it (i think. at least i got a correct solution when i neglected it).
why is this?
 
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Check this example:

http://en.wikipedia.org/wiki/Examples_of_differential_equations

The section "Non-separable first-order linear ordinary differential equations". An arbitrary additive term in the integral in the exponential, can be written as a constant prefactor on [tex]\mu[/tex]. Since the whole equation is multiplied by [tex]\mu[/tex], this is irrelevant for finding the solution.

And you can se in the explicit expression for the final solution y that you have the freedom to redefine [tex]\mu[/tex] by multiplying it ba any nonzero number, since the parameter C is not determined.

Torquil