Why have these endpoints been excluded?

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The discussion centers on the exclusion of endpoints 0 and 24 in the context of finding the derivative of a piecewise function. It is confirmed that the derivative is not defined at the point 9/4 due to discontinuity. The key takeaway is that while the function f(h) includes the endpoints, the derivative's definition requires continuity in a neighborhood around those points, making their inclusion less critical for determining extrema.

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Homework Statement
The problem asks for the derivative of a piecewise function. I don't know why it has excluded the endpoints from the correct answer.
Relevant Equations
f(h) = 4h+10 0<=h<=9/4
f(h) = 0.5sin[2pi/5(h-9/4)]+19 9/4<h<=24
Hi everyone

Could someone please confirm that these solutions are correct? They exclude the endpoints 0 and 24, but I don't understand why, since f(h) includes 0 and 24.

image_2022-05-23_165844737.png


I understand why 9/4 is excluded, as the derivative is not a continuous function.

Thanks
 
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Darkmisc said:
Homework Statement:: The problem asks for the derivative of a piecewise function. I don't know why it has excluded the endpoints from the correct answer.
Generally the derivative of a function ##f## at the point ##a## requires the function to be defined in some neighbourhood of ##a## (i.e. open interval containing ##a##). That said, it's not very important in this case whether we consider ##f'## to be defined at ##0## and ##24## or not.

Darkmisc said:
I understand why 9/4 is excluded, as the derivative is not a continuous function.
Technically the derivative is not defined for ##h = \frac 9 4##.
 
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PeroK said:
That said, it's not very important in this case whether we consider ##f'## to be defined at ##0## and ##24## or not.
The minimum and maximum of a function occur where its derivative is 0 or undefined.
 
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