Why Is a 200 lb Object Falling 200 ft Only Reaching ~23 m/s?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the impact force of a falling object, specifically a 200 lb object falling 200 ft, while considering factors like air resistance and the density of the surface it impacts. The subject area includes physics concepts related to motion, forces, and drag in fluid dynamics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to implement a simulation for calculating impact force, questioning the accuracy of their velocity calculation at impact. They seek clarification on the area used in drag calculations for a human in various free-fall positions.

Discussion Status

Participants have provided feedback on the original poster's code and assumptions, identifying potential errors and suggesting initial tests. There is ongoing exploration of how to determine the cross-sectional area for different human positions during free fall, with some guidance offered regarding the estimation of projected area.

Contextual Notes

The original poster is developing a fall damage calculator for a game, which imposes specific constraints on the calculations, such as the need to account for varying body positions and the complexities of estimating drag in free fall.

Kamiden
Messages
4
Reaction score
0

Homework Statement



  1. I'm trying to write a program to calculate Newtons of impact force from a fall given the weight, general size, shape, and density of an object. I want to take air resistance into account. I also want to take the density of the thing the object falls on into account. I am having trouble figuring out why a 200 lb object falling 200 ft is going ~23 m/s at the point of impact. This is the loop I am using.

  2. For reference:
  3. accel = acceleration, which is set to 9.81 m/s^2 originally.
  4. densitya = density of air, set to 1.2754 kg/m^3
  5. drag = drag coefficient, set to .6 for the shape.
  6. area = area of the object, set at .58 m^3
  7. dragf = drag force in Newtons
  8. weight = weight. Mass in kg * 9.81
  9. mass = mass in kg, 90.7185
  10. rheight = remaining height. This is in meters, and is set to 60.96

  11. while (rheight > 0)
  12. {
  13. time = time + 0.01;
  14. velocity = velocity + (accel*.01);
  15. dragf = ((densitya*drag*area)/2)*(velocity*velocity);
  16. accel = (weight - dragf)/mass;
  17. rheight = rheight - (velocity*.01);
  18. }
  19. count << velocity << " " << time;

  20. Am I getting a formula wrong, is the code bugged, or is it something else?

Homework Equations


Drag Force = (p*Cd*A)/2*v^2
Velocity = d/t
Weight = m * 9.81
Acceleration = W - Df

The Attempt at a Solution


Seen above.
 
Last edited:
Physics news on Phys.org
I think I found your error in line 19. It should read rheight=rheight-velocity*.01. A first test of the program would be to try setting the drag force equal to zero and see if you get a good answer.
 
Thank you. That was causing error, but now I am having a different problem. I have no idea what to use for area. Equations for shapes are easy, but what about for a human in various positions free-falling? (It's a fall damage calculator for a game)

The main ones I'd need to know is kneeling position, prone, and swan dive.
 
Kamiden said:
Thank you. That was causing error, but now I am having a different problem. I have no idea what to use for area. Equations for shapes are easy, but what about for a human in various positions free-falling? (It's a fall damage calculator for a game)

The main ones I'd need to know is kneeling position, prone, and swan dive.
Try reading about skydiving/parachuting. I think with arms spread out, etc., a free fall reaches a limiting velocity of about 100 m.p.h. , but if you google it, you might find the info you need.
 
I tried that. I tried that a lot. The best I get is to find the cross-sectional area. I have no idea how to find the area on a freeform object. Would that just be looking from directly below?

Could I use paint and pixels to feet as a proportion?
 
Kamiden said:
I tried that. I tried that a lot. The best I get is to find the cross-sectional area. I have no idea how to find the area on a freeform object. Would that just be looking from directly below?

Could I use paint and pixels to feet as a proportion?
Projected area would give a suitable estimate. I do think any kind of free fall estimates through the atmosphere is a rather inexact science.
 
Estimates are fine as long as they're at least mostly realistic in this case. Thank you for your help. I got it from here.
 
To convert impact speed to force you would need to know the spring constant of the landing surface.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
11K
  • · Replies 2 ·
Replies
2
Views
8K
  • · Replies 30 ·
2
Replies
30
Views
6K
Replies
18
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
3K