Why is association rule in angular momentum sum not valid?

Click For Summary

Discussion Overview

The discussion centers around the validity of the relation J1 + J2 + J3 ≠ J1 + (J2 + J3) in the context of angular momentum in quantum mechanics, particularly regarding different coupling schemes such as LS coupling and jj coupling. Participants explore the implications of this relation and seek clarification on its proof and significance.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant expresses uncertainty about the proof of J1 + J2 + J3 ≠ J1 + (J2 + J3) and its implications for coupling schemes.
  • Another participant questions the source of the relation, indicating it comes from a less well-known Korean textbook.
  • A participant suggests that the essence of the relation lies in the difference between total angular momentum quantum numbers resulting from LS coupling versus jj coupling.
  • One participant explains that in LS coupling, electron-electron repulsion is stronger than spin-orbit effects, while in jj coupling, the opposite is true, leading to different calculations of total angular momentum.
  • There is a claim that the mathematical expression J1 + J2 + J3 ≠ J1 + (J2 + J3) may not be correct, with the reasoning tied to the treatment of perturbations in the coupling schemes.

Areas of Agreement / Disagreement

Participants express differing views on the mathematical validity of the relation and its implications for angular momentum coupling. There is no consensus on the correctness of the relation or the interpretation of its significance.

Contextual Notes

Participants note the complexity of the proof and the dependence on the definitions and assumptions related to LS and jj coupling schemes. The discussion reflects uncertainty about the mathematical treatment of angular momentum in these contexts.

goodphy
Messages
212
Reaction score
8
Hello.

The quantum mechanics textbook shows the relation of J1 + J2 + J3 ≠ J1 + (J2 + J3). I believe Ji is total angular momentum operator for ith group of electrons (but actually I have not seen J1 operator while I have seen J12 operator so far).

I don't know how to prove J1 + J2 + J3 ≠ J1 + (J2 + J3). I think this play essential role of explaining why there are many coupling schemes.

Please help me to do this:)
 
Physics news on Phys.org
goodphy said:
The quantum mechanics textbook shows the relation of J1 + J2 + J3 ≠ J1 + (J2 + J3).
That's strange, which book did you find this from?
 
blue_leaf77 said:
That's strange, which book did you find this from?

This is actually Korea book so you may not know this. Not famous book but it shows this relation with some proof which is...difficult for me to understand. Have you ever seen this relation? I think essence is this; total angular momentum quantum number J resulted from LS coupling is different to that of being from jj coupling.

Can you at least tell me it is right?
 
goodphy said:
I think essence is this; total angular momentum quantum number J resulted from LS coupling is different to that of being from jj coupling.
The thing about LS and jj coupling schemes is that which effect is larger than which. In LS coupling, the electron-electron repulsion effect is far stronger than the spin-orbit effect and thus the latter is treated as a perturbation. In this case, the zeroth order state is determined by performing the sum ##\mathbf L = \sum_{i=1}^N \mathbf L_i## and ##\mathbf S = \sum_{i=1}^N \mathbf S_i## to obtain ##L## and ##S##. When the spin-orbit perturbation is taken into account, there might be states/terms which are degenerate, so one must switch into using the total angular momentum ##\mathbf J = \mathbf L+\mathbf S##. In JJ coupling case where spin-orbit is much larger than electron-electron repulsion, one calculate ##\mathbf J_i = \mathbf L_i + \mathbf S_i## first, then calculate ##\mathbf J = \sum_{i=1}^N\mathbf J_i##.

My point is, I think writing ##(\mathbf J_1 + \mathbf J_2) + \mathbf J_3 \neq \mathbf J_1 + (\mathbf J_2 + \mathbf J_3)## is not mathematically correct. The reason why the final state in LS and jj coupling differs lies in the question of which effect is taken as perturbation.
 
Last edited:

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
5K