Angular momentum operators in quantum mechanics

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SUMMARY

The discussion centers on the Hamiltonian H=(J1^2+J2^2)2A+J3^2/2B, where J1, J2, and J3 represent angular momentum operators. The user successfully rewrote the Hamiltonian to (J^2-Jz^2)/2A + J3^2/2B and derived the eigenvalues as (h^2L(l+1)-h^2m^2)/2A+h^2m^2/2B. However, the user expressed difficulty in determining the eigenstates associated with this Hamiltonian, specifically questioning the calculation of eigenvalues without the eigenstates |l,m>.

PREREQUISITES
  • Understanding of angular momentum operators in quantum mechanics
  • Familiarity with Hamiltonian mechanics
  • Knowledge of eigenvalues and eigenstates in quantum systems
  • Proficiency in manipulating quantum mechanical equations
NEXT STEPS
  • Study the derivation of eigenstates |l,m> for angular momentum operators
  • Learn about the role of the ladder operators in quantum mechanics
  • Explore the application of the Wigner-Eckart theorem in quantum mechanics
  • Investigate the implications of the quantum mechanical Hamiltonian in different systems
USEFUL FOR

Students and researchers in quantum mechanics, particularly those focusing on angular momentum and Hamiltonian systems, will benefit from this discussion.

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Homework Statement


H=(J1^2+J2^2)2A+J3^2/2B where J1,2,3 are the angular momentum operators and A and B are just numbers


Homework Equations





The Attempt at a Solution


I rewrote the Hamiltonian as (J^2-Jz^2)/2A + J3^2/2B and got the eigenvalues to be (h^2L(l+1)-h^2m^2)/2A+h^2m^2/2B but i don't know how to find the eigenstates of this hamiltonian help
 
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I don't see how you could calculate eigenvalues without using the eigenstates |l,m>
 

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