Why is charge quantized and unable to exist in fractional or decimal values?

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SUMMARY

Charge quantization dictates that electric charge exists only in integral multiples of the elementary charge (e), which is valued at 1.6 x 10-19 C. The equation q = ne, where n is an integer, confirms that charge cannot take on fractional or decimal values. Despite calculations yielding values like 3.2 x 10-19 C for n = 2, these results are still multiples of the fundamental charge and do not represent fractional charges. Therefore, the principle of quantization ensures that any charge divided by 1.6 x 10-19 will yield an integer.

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  • Understanding of electric charge and its properties
  • Familiarity with the concept of quantization in physics
  • Basic knowledge of mathematical operations involving integers
  • Awareness of the significance of the elementary charge (e)
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Homework Statement


Quantisation means charge always exist in integral multiples of magnitude of charge of electron and to put it mathematically we say q = ne, where n is an integer 1,2,3,4 ... -1,-2,-3,... etc. Numerous print and web materials say that charge cannot exist in fraction or decimal, i.e, 2.3e, 4.6e etc. Agreed.

Homework Equations

The Attempt at a Solution


The value of e is 1.6*10^-19 C which itself contradicts the statement that no fraction or decimals is possible while dealing with charge. Also if we take n = 2, we get q = 3.2*10^-19, n =3 means q = 4.8 *10^-19 which are all fractions. Can experts throw light on this aspect? Thanks in advance
 
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It means charge exists in multiples of integers. An easy way to put it is if you divide the value of a charge by 1.6*10^-19, you'll always get an integer and never a fraction.
 

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