Why is charge quantized and unable to exist in fractional or decimal values?

[logearav]

Homework Statement

Quantisation means charge always exist in integral multiples of magnitude of charge of electron and to put it mathematically we say q = ne, where n is an integer 1,2,3,4 ... -1,-2,-3,... etc. Numerous print and web materials say that charge cannot exist in fraction or decimal, i.e, 2.3e, 4.6e etc. Agreed.

Homework Equations

The Attempt at a Solution

The value of e is 1.6*10^-19 C which itself contradicts the statement that no fraction or decimals is possible while dealing with charge. Also if we take n = 2, we get q = 3.2*10^-19, n =3 means q = 4.8 *10^-19 which are all fractions. Can experts throw light on this aspect? Thanks in advance

 

[siddharth23]

It means charge exists in multiples of integers. An easy way to put it is if you divide the value of a charge by 1.6*10^-19, you'll always get an integer and never a fraction.