Why is e^-1 considered the inverse of the natural logarithm?

[Bengo]

Why is e^-1 the inverse of natural log e? Thank you

 

[mathman]

Your question is confusing. Let y = ln(x), then x = e^y. If x = e, y = 1.

 

[Bengo]

Well I was reading a section on charging/ discharging capacitors and this is what it said: charge on a capacitor builds up on the capacitors plates exponentially, indicated in the passage by the repeated appearance in the charge equation of e^-1, the inverse of the natural log e. And I think the equation they are referring to is Q=Qmax(1- e^-1).

 

[mfb]

Could it mean "the inverse of the [basis of the] natural log[,] e"? As e^-1 = 1/e

 

[Bengo]

Could it mean "the inverse of the [basis of the] natural log[,] e"? As e^-1 = 1/e

Ok I'll go with that because it's what I was thinking too. Thank you!