Why is Infrared Radiation the Most Effective for Thermal Effects?

Click For Summary

Homework Help Overview

The discussion centers around the effectiveness of infrared radiation in producing thermal effects compared to other types of electromagnetic radiation. Participants explore the relationship between energy levels of electromagnetic waves and their thermal impact, particularly in the context of everyday temperatures on Earth.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the reasoning behind the assertion that infrared radiation has the most thermal effect, considering the energy of electromagnetic waves. They discuss how different physical processes lead to the emission of various types of radiation and the implications of thermal agitation on infrared emissions.

Discussion Status

The discussion is ongoing, with participants providing insights into the mechanisms of absorption and emission of radiation. Some have suggested that while all wavelengths can induce thermal agitation, infrared radiation is particularly effective due to its resonance with molecular vibrations. There is no explicit consensus yet, as various interpretations and nuances are being explored.

Contextual Notes

Participants are navigating assumptions about the absorption characteristics of different wavelengths and the conditions under which various types of radiation interact with matter. The discussion reflects a mix of scientific concepts and personal interpretations of thermal effects.

PPonte
Why does my schoolbook say that infrared radiation is the electromagentic radiation with most thermal effect?

I thought that the more energetic a certain electromagnetic wave is, greater is her thermal effect.
It seems to me that infrared radiation is the electromagentic radiation with most thermal effect, because for the temperature that the objects on Earth are, it is the radiation whose percentage of absortion is greater, because the emition of this radiation is also the highest.
 
Physics news on Phys.org
The interaction of light and matter is a quantum process - meaning that it occurs in packets, it is not absorbed (or emitted) in continuous quantities. If you look at the spectra (emissions) emitted by atoms you will see spectral lines, indicating that the atoms emit only some enegies of light. Now the reverse is also true - the atoms only tend to absorb only the packets of light that they normally emit. The electromagnetic spectrum is divided into different regions each with different ways in which the rays are generated and detected like at one extreme we find radio waves generated by oscillating charges and at the other end we find gamma rays - extremely high energy electromagnetic waves which are created by oher processes. Matter alos responds differently when absorbing the different types of radiation - ultraviolet gives you a tan while microwaves makes water molecules oscillate to and fro. Infrared emissions are the emissions from bodies that are warm - anybody that is warm emits such radiations. When these emissions are emitted the heat energy escapes in packets from the body. When these packets are absorbed by other bodies they experience an increase in their temperature due to the absorption of the infrared radiation energy.
 
Last edited:
PPonte said:
Why does my schoolbook say that infrared radiation is the electromagentic radiation with most thermal effect?

I thought that the more energetic a certain electromagnetic wave is, greater is her thermal effect.
It seems to me that infrared radiation is the electromagentic radiation with most thermal effect, because for the temperature that the objects on Earth are, it is the radiation whose percentage of absortion is greater, because the emition of this radiation is also the highest.

It`s because different physical processes will lead to different types of electromagnetic waves. For example, atomic transitions in most atoms will lead to emission (or absorption) of UV, IR and visible wavelengths.

Many nuclear transitions lead to emission of gamma rays.

Now, atoms which are moving around due to thermal agitation emit mostly in the infrared (at ''normal'' temperatures...If you go to sevreal thousand Kelvins or beyond, thermal agitation will lead to visible wavelength emission or even UV and so on). This radiation is due to their thermal agitation and not to atomic transitions.
 
nrqed said:
It`s because different physical processes will lead to different types of electromagnetic waves. For example, atomic transitions in most atoms will lead to emission (or absorption) of UV, IR and visible wavelengths.

Many nuclear transitions lead to emission of gamma rays.

Now, atoms which are moving around due to thermal agitation emit mostly in the infrared (at ''normal'' temperatures...If you go to sevreal thousand Kelvins or beyond, thermal agitation will lead to visible wavelength emission or even UV and so on). This radiation is due to their thermal agitation and not to atomic transitions.

Just to add something: I have talked about emission but similar reasoning applies to absorption.

If the molecules in your hand are bombared with infrared radiation, it will tend to move them around, creating heat. If they are bombared with gamma rays (let`s say), the gamma rays will be tend to break the bonds and other nasty effects.
 
nrqed said:
If the molecules in your hand are bombared with infrared radiation, it will tend to move them around, creating heat. If they are bombared with gamma rays (let`s say), the gamma rays will be tend to break the bonds and other nasty effects.

Thank you. This was the precise point.
But look, although the gamma rays break bonds, will not they also heat my hand?

And if a beam of visible light is inciding in my hand? It will not break bonds. But it is not also true that it will heat my hand and not just more than an infrared beam would do, because an considering percentage of the photons will not be absorbed?
 
PPonte said:
Thank you. This was the precise point.
But look, although the gamma rays break bonds, will not they also heat my hand?

And if a beam of visible light is inciding in my hand? It will not break bonds. But it is not also true that it will heat my hand and not just more than an infrared beam would do, because an considering percentage of the photons will not be absorbed?


To get really to the core of the answer would invoke the phenomenon of resonance. Are you familiar with this?

The key point is that, sure, all wavelengths will create a little bit of thermal agitation. But a *large* effect is only produced by a certain range of wavelengths, in the IR part. Ìf you push and pull at certain frequency on a child on a swing, you will make it move back and forth. But certain frequencies will cause larger oscillation. It is not true that the faster you push and pull the higher the child will swing.

Patrick
 
nrqed said:
To get really to the core of the answer would invoke the phenomenon of resonance. Are you familiar with this?

The key point is that, sure, all wavelengths will create a little bit of thermal agitation. But a *large* effect is only produced by a certain range of wavelengths, in the IR part. Ìf you push and pull at certain frequency on a child on a swing, you will make it move back and forth. But certain frequencies will cause larger oscillation. It is not true that the faster you push and pull the higher the child will swing.

Patrick

Perfect. Thank you very much!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
5K
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
8
Views
5K
  • · Replies 29 ·
Replies
29
Views
5K
  • · Replies 19 ·
Replies
19
Views
18K
  • · Replies 2 ·
Replies
2
Views
2K