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Why ln(k) when k is a possitive integer, ln(k) is a complex number?
The discussion centers on the nature of the natural logarithm function, specifically why \(\ln(k)\) is considered a complex number when \(k\) is a positive integer. Participants clarify that the natural logarithm can be expressed in terms of complex numbers using Euler's formula, which states that \(\ln(k) = \ln|k| + i\arg(k)\). Since \(k\) is a positive integer, \(\arg(k)\) equals zero, leading to \(\ln(k) = \ln(k) + 0i\), thus confirming that \(\ln(k)\) is indeed a complex number with an imaginary part of zero.
PREREQUISITESMathematicians, students of complex analysis, and anyone interested in the properties of logarithmic functions in the context of complex numbers.