Why is parity maximally violated in weak interactions?

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SUMMARY

Parity is maximally violated in weak interactions, specifically in W boson interactions, while Z bosons couple to both left and right-handed particles, indicating that parity is not maximally violated in their case. The electroweak symmetry breaking results in W bosons becoming massive while the Z boson and photon emerge from the mixing of the unbroken symmetry components. This phenomenon highlights the unique characteristics of weak interactions, particularly the distinction between charged and neutral currents. The term "maximally violated" originated 50 years ago, referring to the equal parts of vector (V) and axial vector (A) interactions observed in charged current weak interactions.

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Why do they always say parity is maximally violated in weak interaction? This is true for W boson interactions. But not for Z bosons, as the Zs couple to both left and right handed particles. And hence, is not maximally violated in the case of Z.
 
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Electroweak symmetry is broken; this is one symptom. The unbroken symmetry contains a w1, w2 and w3 that couple to left-handed fermions and a B0 that couples to both handednesses. When the symmetry breaks, the w1 and w2 become the massive W+ and W-, but the w3 and B0 mix to produce a photon which couples to both, and a Z0 which couples purely left-handedly to neutral particles, and progressively more right-handedly to particles with more charge.
 
touqra said:
Why do they always say parity is maximally violated in weak interaction? This is true for W boson interactions. But not for Z bosons, as the Zs couple to both left and right handed particles. And hence, is not maximally violated in the case of Z.
The term "maxilmally violated" arose 50 years ago because the charged current weak interactions, which were the only ones seen for a long time, had equal parts of V and A.
 

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