Why Is the AMU Calculation Using 12 x 10⁻³ Instead of Just 12?

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SUMMARY

The discussion centers on the calculation of atomic mass unit (AMU) using the formula 12 x 10⁻³ divided by Avogadro's number, which equals 1.99264654 x 10⁻²⁶ grams. Participants clarify that the correct approach involves using 12 grams per mole, not just 12, to account for the scale of atomic measurements. The confusion arises from the notation and the importance of units in scientific calculations, particularly in the context of carbon-12 (¹²C₆) and its relation to Avogadro's number (6.023 x 10²³).

PREREQUISITES
  • Understanding of atomic mass unit (AMU) calculations
  • Familiarity with Avogadro's number (6.023 x 10²³)
  • Basic knowledge of unit conversion in chemistry
  • Concept of moles in chemical measurements
NEXT STEPS
  • Study the concept of atomic mass and its calculation methods
  • Learn about the significance of Avogadro's number in chemistry
  • Explore unit conversion techniques in scientific calculations
  • Investigate the properties of carbon-12 and its applications in chemistry
USEFUL FOR

Chemistry students, educators, and anyone involved in scientific calculations related to atomic mass and molecular measurements will benefit from this discussion.

Indranil
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Homework Statement


This the calculation of AMU. I don't understand the calculation. The calculation is below:
¹²C₆ = 6.023 X 10²³
12 X 10⁻3 / Avogadro number = 1.99264654 X 10⁻²⁶
Why 12 X 10⁻3 it should be only 12 / Avogadro number
I am confused. Please simplify it.

Homework Equations


This the calculation of AMU. I don't understand the calculation. The calculation is below:
¹²C₆ = 6.023 X 10²³
12 X 10⁻3 / Avogadro number = 1.99264654 X 10⁻²⁶
Why 12 X 10⁻3 it should be only 12 / Avogadro number

The Attempt at a Solution


¹²C₆ = 6.023 X 10²³
12 / Avogadro number = 1.99264654 X 10⁻²⁶ g
 
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The question is set out too confusedly to know what it is.
Please try again: give quotes if there is some text that is confusing you.
12/(6.023 X 10²³) g should be the mass of an atom of 12C.
I do not know what C6 is in this context.
 
Last edited:
As your instructor has undoubtedly told you millions of times, units are important.
 

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