Estimating Avogadro's Number Using Surface Tension Experiment

  • Thread starter Thread starter JM92
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around estimating Avogadro's number through a surface tension experiment involving n-butanol in water, utilizing the capillary rise method and the Gibb's adsorption equation. Participants explore the calculations related to the number of moles adsorbed, the dimensions of molecules, and the implications of these calculations on the estimation of Avogadro's number.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculated the number of moles adsorbed at the surface per unit area and derived a height for the monolayer based on the assumption that the surface is a monolayer of n-butanol molecules.
  • The calculated height of the molecule was found to be 0.459 cm, which led to concerns about the validity of this result, as it seemed unreasonably large for a single molecule.
  • Another participant echoed the concern about the height per molecule, suggesting that it indicates a significant error in the calculations.
  • A later reply inquired if the problem had been resolved, indicating ongoing uncertainty about the calculations and the approach taken.

Areas of Agreement / Disagreement

Participants generally agree that the calculated height per molecule appears incorrect, but there is no consensus on how to properly approach the problem or resolve the discrepancies in the calculations.

Contextual Notes

Participants have not resolved the mathematical steps leading to the estimation of Avogadro's number, and there are indications of missing assumptions or misinterpretations in the calculations.

JM92
Messages
9
Reaction score
0

Homework Statement



I did a surface tension experiment with n-butanol in water using the capillary rise method. Using my data and the Gibb's adsorption equation, I found the number of moles adsorbed at the surface per unit area to be
n/A = 5.012 x 10-3 mol⋅cm-2.

I also calculated the radius of the capillary to be r = 0.0386273 cm.

Given that the density of n-butanol is assumed to be the same as water ρ = 0.9970 g⋅cm-3
and the molar volume of n-butanol is Vm = 91.5 cm3⋅mol-1, estimate Avogadro's number.

Also assume the surface is a monolayer of n-butanol molecules, and that an n-butanol molecule is a cube.

Homework Equations



Vmolecule = Vcube = h3

Vmonolayer = Vcylinder = πr2h

h = Vm/(n/A)

# of molecules = Vmonolayer/Vmolecule

n = (n/A)πr2

NA = Avogadro's number = # of molecules/n

The Attempt at a Solution



Since the surface is a monolayer, I think the length of a molecule is the height of the monolayer.
h = 91.5cm3⋅mol-1/5.012 x 10-3 mol⋅cm-2 = 0.459 cm

Now I can calculate the volume of a single cubic molecule to be:
Vmolecule = h3 = (0.459 cm)3 = 0.0964 cm3

and the volume of the monolayer is:
Vmonolayer = π(0.0386273 cm)2(0.459 cm) = 2.15 x 10-3 cm3

(This must already be incorrect since the volume of a single molecule can't be larger than that of the whole monolayer of molecules).

The number of molecules would incorrectly be:
# of molecules = (2.15 x 10-3 cm3)/(0.0964 cm3) = 0.0223 molecules

The number of moles is:
n = (5.012 x 10-3 mol⋅cm-2)(0.0386273 cm)2π = 2.349 x 10-5 mol

Then Avogadro's number is calculated as:
NA = (0.0223 molecules)/(2.349 x 10-5 mol) = 949 molecules/mol

..which is unbelievably wrong. Any help is appreciated!
 
Physics news on Phys.org
JM92 said:
Since the surface is a monolayer, I think the length of a molecule is the height of the monolayer.
h = 91.5cm3⋅mol-1/5.012 x 10-3 mol⋅cm-2 = 0.459 cm

0.459 cm per molecule already should tell you something is terribly wrong at this stage.
 
Borek said:
0.459 cm per molecule already should tell you something is terribly wrong at this stage.
Right, didn't notice that. Do you have any suggestions on how I could properly start this then? Thank you!
 
Was this ever solved?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 1 ·
Replies
1
Views
19K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
3
Views
26K