Why is the calculated change in PE for a mass on a spring incorrect?

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SUMMARY

The discussion centers on calculating the change in potential energy (PE) for a mass on a spring system. A mass of 0.5 kg is suspended from a spring with a spring constant of 40 N/m, resulting in an extension of 0.123 m. The calculated change in PE using the formula energy = 0.5kx² yields 0.30 J, which is identified as incorrect because it represents the energy stored in the spring rather than the change in gravitational potential energy of the mass. The key takeaway is that energy is not conserved in this scenario as the mass passes through the equilibrium position with kinetic energy.

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Homework Statement


A spring of length 75cm has a mass of 0.5kg hanging from it.
If the spring constant = 40N/m calculate:
a) the extension of the spring
b) The change in PE of the mass


Homework Equations


Part (a) is easy x = (0.5 x 9.81)/40 = 0.123m
Part (b) energy = 0.5kx^2 gives 0.30J which is WRONG !

WHY ?


The Attempt at a Solution


 
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Hi Emilyjoint! :smile:
Emilyjoint said:
A spring of length 75cm has a mass of 0.5kg hanging from it.
If the spring constant = 40N/m calculate:

b) The change in PE of the mass

part (b) energy = 0.5kx^2 gives 0.30J which is WRONG !

that's the energy of the spring

(energy is not conserved … if you released the mass from rest, it would sail through that equilibrium position at high speed, wouldn't it? :wink:)
 

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