Why Is the Calculated Velocity for Lifting a Person in a Wind Tunnel So Low?

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SUMMARY

The calculated velocity for lifting a person in a wind tunnel is significantly low due to the mass of air and its interaction with gravity. The formula used, mass of air multiplied by velocity equals mass of man multiplied by gravity, yields a velocity of 0.06 m/s when using a mass of air of 10,000 kg. This calculation does not account for the actual air resistance and the effective mass of air interacting with a person. In practical applications, such as indoor skydiving, air velocities around 100 mph can effectively suspend individuals.

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  • Familiarity with the principles of momentum conservation
  • Knowledge of air resistance and its effects on objects
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Suyash Singh
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mass of air X velocity = mass of man x gravity
(10000)x(v)=60x10
velocity=600/10000
how come velocity is so less?
I am still in school so forgive me if my calculations look stupid.
 
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Suyash Singh said:
mass of air X velocity = mass of man x gravity
(10000)x(v)=60x10
velocity=600/10000
how come velocity is so less?
I am still in school so forgive me if my calculations look stupid.
It depends on the size of the wing... :smile:
 
Or do you mean like indoor skydiving?

https://www.iflyworld.com/

https://www.tmtmtour.com/wp-content/uploads/2018/01/ifly2.jpg
ifly2.jpg
 

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berkeman said:
Or do you mean like indoor skydiving?

https://www.iflyworld.com/

https://www.tmtmtour.com/wp-content/uploads/2018/01/ifly2.jpg
View attachment 225341
i was talking about thunderstorm
there is a storm coming to Delhi with speed 60 kmph.
I was thinking if people would start flying. Or maybe the small dogs on street.
 
Suyash Singh said:
i was talking about thunderstorm
there is a storm coming to Delhi with speed 60 kmph.
I was thinking if people would start flying. Or maybe the small dogs on street.
Looks like 60-80mph is pretty close to the limit...

https://i.ytimg.com/vi/ITBq82c6RzY/maxresdefault.jpg

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It seems that nobody has really addressed your attempt at calculation. Where did you obtain that formula from, and also what made you chose 10,000kg as your mass of air?
 
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cjl said:
It seems that nobody has really addressed your attempt at calculation. Where did you obtain that formula from, and also what made you chose 10,000kg as your mass of air?
I thought that
momentum of air= force on man by earth
also mass of air per square metre=10000kg
 
cjl said:
It seems that nobody has really addressed your attempt at calculation
Hey, who you calling "nobody"?! :biggrin:
 
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berkeman said:
Hey, who you calling "nobody"?! :biggrin:
I meant directly addressing the calculation rather than the end result. You did address a number of the factors though
 
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  • #10
Suyash Singh said:
I thought that
momentum of air= force on man by earth
also mass of air per square metre=10000kg
Momentum isn't the worst place to start here, but I'll address that more after we look at the mass some more. 10,000 kg is about right if you're looking at the entire column of air from the ground up to space, but what bearing would that have on its ability to lift a person? If a person is standing in the wind, what mass of air actually interacts with them?
 
  • #11
Suyash Singh said:
I thought that
momentum of air= force on man by earth
On that track you will find out what happens when you hit somebody with 10 tons of air in one go. (But the equation is still wrong.)

What you really need is indeed the "force on man by earth", but what balances it is the air resistance (try look it up).
 
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  • #12
Rive said:
On that track you will find out what happens when you hit somebody with 10 tons of air in one go. (But the equation is still wrong.)

What you really need is indeed the "force on man by earth", but what balances it is the air resistance (try look it up).
conservation of momentum
2 x mass of air x velocity (since air velocity won't change)=m(0)+ m(v)
2x 10000 x velocity=60v
 
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Suyash Singh said:
conservation of momentum
That's an excellent tool for collisions, for example: but for this, you better to swim instead.
 
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  • #14
My grandson "flew" in one of those iFLY vertical wind tunnels and he and his adult "instructor" where suspended with a air velocity of about 100 mph. The force of wind applied perpendicularly on a one sq foot surface is about 49 lbs.
 
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