Why Is the Calculation of Santa Ana Wind Temperatures Tricky?

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Homework Help Overview

The discussion revolves around the calculation of temperature changes in air as it descends from a higher elevation to sea level, specifically focusing on the phenomenon of Santa Ana winds. The original poster presents a problem involving the relationship between pressure and temperature during this process, highlighting the adiabatic nature of the air movement.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the air not exchanging heat with its surroundings and question the relationship between pressure and temperature in this context. There is a discussion about the adiabatic process and its effects on volume and temperature, with attempts to apply relevant equations.

Discussion Status

Some participants have offered guidance on using adiabatic relations and have confirmed the validity of certain approaches. Multiple interpretations of the problem are being explored, particularly regarding the application of specific heat ratios and the relationships between pressure, volume, and temperature.

Contextual Notes

There is an emphasis on the adiabatic process and the specific heat ratio of air, which may influence the calculations. The original poster's initial approach appears to have overlooked some of these factors, leading to questions about the assumptions made in the problem setup.

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Easy question--but what's wrong?

Homework Statement


When strong winds rapidly carry air down from mountains to a lower elevation, the air has no time to exchange heat with its surroundings. The air is compressed as the pressure rises, and its temperature can increase dramatically. These warm winds are called Chinook winds in the Rocky Mountains and Santa Ana winds in California. Suppose the air temperature high in the mountains behind Los Angeles is 0 degrees C at an elevation where the air pressure is 60 kPa. What will the air temperature be, in C when the Santa Ana winds have carried this air down to an elevation near sea level where the air pressure is 100 kPa ?


Homework Equations





The Attempt at a Solution



This is a pretty straightforward problem, but for some reason I got the answer wrong.

P1/T1=P2/T2

(60kPa)/(273K) = (100kPa)/(T2) T2=455K = 180 degrees C
 
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The important phrase is that the air has no time to exchange heat with its surroundings. What does that signify? What relationship between P and T is true in that case?
 
Hmmm... again I forgot that volume changes, and this is an adiabatic process, and volume decreases

For an adiabatic process: P1V1^gamma = P2V2^gamma

Gamma is the specific heat ratio
gamma= Cp/Cv

since air is a mixture of mostly diatomic gases oxygen & nitrogen gamma = 29/20.8 = 1.40

so (60 kPa)(V1)^1.40 = (100kPa)(V2)^1.40
the ratio of V2/V1 = .694

P1V1/T1 = P2V2/T2

(60kPa)(V1)/(273 K) = (100kPa)(V2)/T2
(.220)*T2 = (V2)/(V1) * (100 kPa)
.220T2= 69.4
T2= 314.45 K = 42.45 degrees C

Is this anywhere near how I should approach this problem?
 
Anybody have any thoughts about this? Thanks.
 
That looks right to me. To save yourself a step or two you can also use the adiabatic relation for P and T directly:

<br /> P^{\gamma -1} T^{-\gamma} = \mbox{ constant}<br />

and there is also one for T and V only. But of course that is essentially what you did.
 

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