Why is the CFSE for d6 not equal to -24Dq+3p in crystal field theory?

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SUMMARY

The discussion centers on the calculation of Crystal Field Stabilization Energy (CFSE) for d6 electron configurations in octahedral complexes, specifically addressing why CFSE is represented as -24Dq + 2p rather than -24Dq + 3p. Participants reference the stabilization energies for d4 to d8 configurations, highlighting the importance of electron pairing in determining the CFSE. The conversation also touches on the implications of strong field versus weak field ligands and their effects on electron pairing energy.

PREREQUISITES
  • Understanding of Crystal Field Theory (CFT)
  • Familiarity with octahedral complexes and their electron configurations
  • Knowledge of pairing energy and its role in CFSE calculations
  • Basic grasp of ligand field strength and its impact on electron distribution
NEXT STEPS
  • Study the derivation of CFSE equations for various d-electron configurations
  • Explore the differences between strong field and weak field ligands in CFT
  • Learn about the implications of electron pairing on CFSE in octahedral complexes
  • Investigate the role of specific metal-ligand interactions in determining CFSE
USEFUL FOR

Chemistry students, researchers in coordination chemistry, and professionals studying transition metal complexes will benefit from this discussion, particularly those focused on Crystal Field Theory and its applications in predicting electronic behavior in octahedral complexes.

flashmanbs
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at crystal field stabilization in strong field case
d4 CFSE=-16Dq+p
d5 CFSE=-20Dq+2p
d6 CFSE=-24Dq+2p
d7 CFSE=-18Dq+p
d8 CFSE=-12Dq
it was shuld be +3P and +4 P
why it be +p,2p,2p,p ?
 
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flashmanbs said:
at crystal field stabilization in strong field case
d4 CFSE=-16Dq+p
d5 CFSE=-20Dq+2p
d6 CFSE=-24Dq+2p
d7 CFSE=-18Dq+p
d8 CFSE=-12Dq
it was shuld be +3P and +4 P
why it be +p,2p,2p,p ?


Why do you believe that it should be + 3 and + 4? What equation are you using?
 
my Q explain why the CFSE =-24Dq+2p at d6 not =-24Dq+3p?
like u see in fig. if we put the 6`th electron we have 3 paring set so we was should add 3p to the CFSE why we count them as 2P?
2628rbc.jpg
 
flashmanbs said:
my Q explain why the CFSE =-24Dq+2p at d6 not =-24Dq+3p?
like u see in fig. if we put the 6`th electron we have 3 paring set so we was should add 3p to the CFSE why we count them as 2P?
2628rbc.jpg

You are right for this case where its Octahedral , scroll the link to page 9

http://www.chemistry.ucsc.edu/~tholman/Chem151A/LectureNotes/Week2.pdf

Is this an Octahedral complex? Also did they mention a specific metal ligand complex ; sometimes an LS becomes HS should the actual CFSE is found to be positive with the incorporation of the pairing energy?
 
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