Snippy Messages 5 Reaction score 0 Thread starter Jun 12, 2010 #1 Why is the characteristic of (d/dx) + (d/dt) = 0 where d is small delta c = x - t and not c = x + t
elibj123 Messages 237 Reaction score 2 Jun 13, 2010 #2 Because[tex](\partial_{x}+\partial_{t})f(x+t)=2f'(x+t)[/tex] While [tex](\partial_{x}+\partial_{t})f(x-t)=f'(x-t)-f'(x-t)=0[/tex] So you need solutions of the latter form u(x,t)=f(x-t), which means x-t=const are charcteristic lines.
Because[tex](\partial_{x}+\partial_{t})f(x+t)=2f'(x+t)[/tex] While [tex](\partial_{x}+\partial_{t})f(x-t)=f'(x-t)-f'(x-t)=0[/tex] So you need solutions of the latter form u(x,t)=f(x-t), which means x-t=const are charcteristic lines.