Why is the characteristic of (d/dx) + (d/dt) = 0 not c = x + t?

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    2nd order Pde
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Why is the characteristic of

(d/dx) + (d/dt) = 0 where d is small delta

c = x - t and not c = x + t
 
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Because[tex](\partial_{x}+\partial_{t})f(x+t)=2f'(x+t)[/tex]

While

[tex](\partial_{x}+\partial_{t})f(x-t)=f'(x-t)-f'(x-t)=0[/tex]

So you need solutions of the latter form u(x,t)=f(x-t), which means x-t=const are charcteristic lines.