Why Is the Differential Equation m*dv/dt = mg - kv^2 Challenging to Solve?

  • Context: Undergrad 
  • Thread starter Thread starter Robert Mak
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around the differential equation m*dv/dt = mg - kv^2, focusing on the challenges associated with solving it. Participants explore the mathematical reasoning behind the equation and its implications in the context of motion and forces.

Discussion Character

  • Technical explanation, Mathematical reasoning, Homework-related

Main Points Raised

  • One participant expresses difficulty in finding a solution to the differential equation.
  • Another participant attempts to manipulate the equation, suggesting a separation of variables approach.
  • A third participant acknowledges the previous response with a light-hearted comment, indicating a realization of the method presented.
  • Another participant references an external source, specifically a Wikipedia article on terminal velocity, as a place to find the full solution.

Areas of Agreement / Disagreement

The discussion does not reach a consensus on the solution to the differential equation, as participants are at different stages of understanding and problem-solving.

Contextual Notes

Some assumptions regarding the constants and the conditions under which the equation is applied may not be fully articulated. The discussion also reflects varying levels of familiarity with the topic among participants.

Who May Find This Useful

Readers interested in differential equations, motion under forces, or those seeking clarification on solving similar mathematical problems may find this discussion relevant.

Robert Mak
Messages
26
Reaction score
0
m[tex]\frac{dv}{dt}[/tex]= mg - kv[tex]^{2}[/tex]

constants: m, g, k.

I tryed and i can't find a solution to this diferential equation.
 
Physics news on Phys.org
[tex]m \frac{dv}{dt}=mg-kv^2[/tex]

[tex]\Rightarrow \frac{m}{mg-kv^2} \frac{dv}{dt}=1[/tex]

[tex]\Rightarrow \frac{m}{mg-kv^2} dv=1 dt[/tex]


Able now?
 
thanks; lol i didnt saw it
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K