PSOA
Why is the end area of shell [tex]2\pi rdr[/tex]?
Thanks in advance.
The discussion revolves around understanding why the end area of a cylindrical shell is represented as 2πrdr in the context of the moment of inertia formula. The topic is situated within the realm of calculus and physics, particularly focusing on integration and differential areas.
The discussion is active, with participants engaging in clarifying the concept of differential areas and integration. One participant acknowledges understanding the explanation provided, indicating a productive exchange of ideas, though no consensus on the broader implications of the moment of inertia is reached.
Participants mention the learning process of integration, suggesting that some may be new to the topic and are navigating through foundational concepts.
PSOA said:![]()
Why is the end area of shell [tex]2\pi rdr[/tex]?
Thanks in advance.![]()
What award ?PSOA said:And congratulations for the award!