Why Is the Hermiticity of the Density Operator Important in Quantum Mechanics?

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The density operator in quantum mechanics must be Hermitian because its eigenvalues represent probabilities, which are inherently real and non-negative. This property ensures that the probabilities do not exceed 1, maintaining physical validity. The diagonal elements of the density matrix do not provide meaningful information until the matrix is diagonalized. The discussion also touches on the use of the density operator in a two-level system, specifically through the Heisenberg equation of motion. Hermiticity is derived from the definition of the density operator, which involves summing over probabilities associated with quantum states.
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Hi there,
In all text of QM I have, they tells that the density operator is hermitian. But without considering the math, from the physics base, why density operator must be hermitian? What's the physical significane of the eigenvalue of density matrix?

Thanks
 
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Eigenvalues of the density matrix are probabilities. They clearly must be real, which is why the matrix must be hermitian. (In addition, they also must be non-negative and not larger than 1.)
 
Demystifier said:
Eigenvalues of the density matrix are probabilities. They clearly must be real, which is why the matrix must be hermitian. (In addition, they also must be non-negative and not larger than 1.)

Thanks. So before diagonalization, the diagonal elements of density matrix don't tell anything , right?
 
Well, I understand now how the diagonalized density matrix works. But for the following case how do I use it? For example, I have a two-level system without interaction, and hamiltonian gives

H|\Psi_n\rangle = \hbar\omega_n |\Psi_n\rangle

Now I consider the Heisenberg equation of the density operator

\dot{\rho} = -\frac{i}{\hbar}[H,\rho]

to findout the element of \dot{\rho}_{nm}, I apply an eigenstate of H on both side

\dot{\rho}|\Psi_i\rangle = -\frac{i}{\hbar}(H\rho - \rho H)|\Psi_i\rangle<br /> = -\frac{i}{\hbar}(H-\omega_i)\rho|\Psi_i\rangle<br />

So, what is \rho|\Psi_i\rangle? In the text, it gives

\dot{\rho}_{nm} = -i\omega_{nm}\rho_{nm} ?
 
Demystifier said:
Eigenvalues of the density matrix are probabilities. They clearly must be real, which is why the matrix must be hermitian. (In addition, they also must be non-negative and not larger than 1.)

Real eigenvalues does not imply hermiticity - for example, look at "[URL Hermiticity of the density matrix follows from its definition, which is

<br /> \rho := \sum_k p_k |\psi_k\rangle\langle\psi_k|<br />

where p_k is the probability that system will be found in the state \psi_k (states \psi_k can be arbitrary possible states of the system).
 
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Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA

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