Why is the intensity of waves in destructive interference still 2(A^2)?

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Homework Help Overview

The discussion revolves around the concept of wave intensity in the context of destructive interference. The original poster questions why the intensity remains at 2(A^2) despite the expectation that destructive interference would result in zero intensity, given that the waves are of the same amplitude but in antiphase.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the nature of destructive interference, questioning whether it can be complete and discussing the implications of phase differences on intensity. Some express confusion regarding the calculations of average intensity and the relationship between power and intensity.

Discussion Status

The discussion is ongoing, with participants providing insights and clarifications about the nature of wave interference. Some have offered explanations regarding phase differences and their effects on intensity, while others continue to seek further understanding of the concepts involved.

Contextual Notes

There are references to diagrams that are not clearly visible to all participants, which may hinder understanding. Additionally, there is mention of specific phase differences that lead to varying interference effects, indicating a need for clarity on these concepts.

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Homework Statement



i don't understand why the intensity of waves due to destructive inteference is still 2(A^2 )... since this is destructive inteference why not the wave intensity=0? both waves are of same amplitude but antiphase. Am i right?

Homework Equations





The Attempt at a Solution

 

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destructuve interference need not be completely destructive... I think the phase diagram in your second pic shuld make the situation plain.
However, I cannot read the writing in the pics.
 
Agree---pics too small.
 
Simon Bridge said:
destructuve interference need not be completely destructive... I think the phase diagram in your second pic shuld make the situation plain.
However, I cannot read the writing in the pics.
here's the clearer pics. hopefully you can help.

i don't understand why the intensity of waves due to destructive inteference is still 2(A^2 )... since this is destructive inteference why not the wave intensity=0? both waves are of same amplitude but antiphase. Am i right?
refer to the third pic
 

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Part (b) has two section - one where the phase difference produces total destructive interference and another where the phase difference is one-third that required for total destructive interference.
Since 180deg is required for total destruction, one-third of this is 60deg which is the phase difference shown in the third pic.
 
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Simon Bridge said:
Part (b) has two section - one where the phase difference produces total destructive interference and another where the phase difference is one-third that required for total destructive interference.
Since 180deg is required for total destruction, one-third of this is 60deg which is the phase difference shown in the third pic.

sorry. i still don't understand. can you explain further? i can't understand why the average amplitude is as in the photo,

since three vector in the same direction, i would do in this way,
adding up all the vector in clockwise direction, i would get 3(A^2)-(A^2)+(A^2)=3(A^2) magnitude of y1-y2=3(A^2) whereas y1=y2=(A^2)
 

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why average intensity is used? and i don't understand how is the average intensity calculated.
 
Question b(ii) concerns power carried by the waves.
How is the power related to the intensity?
 
Simon Bridge said:
Question b(ii) concerns power carried by the waves.
How is the power related to the intensity?
intensity=power/area

why average intensity is used? and i don't understand how is the average intensity calculated.

why can't the phase difference of pi/3 leads to constructive intefreence?
 
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  • #10
intensity=power/area
When it is a wave - the intensity is the average power (over one wavelength), per unit area.

##P=I_{ave}A##

http://en.wikipedia.org/wiki/Intensity_(physics )
http://webpages.ursinus.edu/lriley/courses/p212/lectures/node18.html

The instantaneous intensity is proportional to the instantaneous amplitude squared.
For a stationary target, this will increase and decrease as the wave arrives.
i.e waves arriving at the beach deliver energy in surges, back and forth.
 
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  • #11
do you mean the author is finding the average intensity of constructive superposition and desrtuctive superposition? where constructive superposition leads to 3A^2 , and destructive superposition leads to A^2 ?
 
  • #12
Simon Bridge said:
When it is a wave - the intensity is the average power (over one wavelength), per unit area.

##P=I_{ave}A##

http://en.wikipedia.org/wiki/Intensity_(physics )
http://webpages.ursinus.edu/lriley/courses/p212/lectures/node18.html

The instantaneous intensity is proportional to the instantaneous amplitude squared.
For a stationary target, this will increase and decrease as the wave arrives.
i.e waves arriving at the beach deliver energy in surges, back and forth.
the upper part is for constructive superposition, the lower part is for desrtuctive superposition, the upper part shows phase difference of 60 degree... but the lower part shows phase difference of 120. (but not 60 degree) how can this happen? I know that constructive superposition occurs when phase difference less than 180 degree. Whereas destructive superposition occurs when phase difference more than 180.. is my conceptand working correct?
 

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  • #13
A phase difference greater than 180° is the same as a phase difference less than 180°. For example, phase difference of 200° is the same as a phase difference of 160°.

Perhaps generalize the topic this way:

When a pair of sine waves each of amplitude A superimpose at some point such that the resultant sine wave has

(i) an amplitude > A then we have constructive interference;

(ii) an amplitude < A then we have destructive interference;

(iii) an amplitude = A then we have no interference. :smile:

Question for desmond iking: What phase difference is needed to give condition (iii)?
 
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  • #14
0...
 
  • #15
NascentOxygen said:
A phase difference greater than 180° is the same as a phase difference less than 180°. For example, phase difference of 200° is the same as a phase difference of 160°.

Perhaps generalize the topic this way:

When a pair of sine waves each of amplitude A superimpose at some point such that the resultant sine wave has

(i) an amplitude > A then we have constructive interference;

(ii) an amplitude < A then we have destructive interference;

(iii) an amplitude = A then we have no interference. :smile:

Question for desmond iking: What phase difference is needed to give condition (iii)?

i can understand why phase angle 160=200.. for the second diagram, i can also say that 120=240 degree... but this doesn't comply with the statement that the phase difference between A1 and A2 is 60
 
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  • #16
The second diagram seems to show subtracting one from the other, whereas superposition involves addition.
 
  • #17
desmond iking said:
do you mean the author is finding the average intensity of constructive superposition and desrtuctive superposition? where constructive superposition leads to 3A^2 , and destructive superposition leads to A^2 ?
Go back t the question - what does it say?
 

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