Why is the QCD Lagrangian often abbreviated?

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Kara386
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The QCD Lagrangian is
##\mathcal{L}=-\frac{1}{4}G^{a}_{\mu\nu}G^{a\mu\nu}+\sum\limits_{j=1}^n \left[\bar{q}_j\gamma^{\mu}iD_{\mu}q_j - (m_jq^{\dagger}_{Lj}q_{Rj}+h.c.)\right]+\frac{\theta g^2}{32\pi^2}G^{a}_{\mu\nu}\widetilde{G}^{a\mu\nu}##
Why is it so often quoted as just
##\mathcal{L}=-\frac{1}{4}G^{a}_{\mu\nu}G^{a\mu\nu}+\sum\limits_{j=1}^n \left[\bar{q}_j\gamma^{\mu}iD_{\mu}q_j - (m_jq^{\dagger}_{Lj}q_{Rj}+h.c.)\right]##?
I've seen both and I'm assuming the longer one is more complete somehow, but in those cases where the short version is being used, there's not even a mention of the missing term.
 
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Observationally, ##\theta = 0## to experimental precision. The presence of the last term would introduce CP violation that is not observed. Why this is the case is known as the strong CP problem. One possible solution is the Peccei-Quinn mechanicsm.
 
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