Why is the scale reading 397 N when the elevator is slowing down?

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SUMMARY

The scale reading of 397 N occurs when a person stands on it in an elevator that is decelerating. Initially, the scale reads 587 N when the elevator accelerates upwards. The discrepancy arises because the scale measures the apparent weight, which changes due to the elevator's acceleration. When the elevator is slowing down, the scale reflects a lower reading of 397 N, indicating that the person’s actual weight is not being fully supported by the scale during deceleration.

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Homework Statement


this should be simple question, but i could not get the answer. hope someone could point out my mistake.

A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 587 N. Later, as the elevator later stops, the scale reading is 397 N. Assume the magnitude of the acceleration is the same during starting and stopping.

The Attempt at a Solution


Determine the weight of the person
it should be 397N, since the scale shows 397N when the elevator stops. but my answer is wrong. why?
 
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The elevator is stopping, not stopped, when the scale reads 397 N.
 
As written, the question is poorly stated. They mean: While the elevator is speeding up, the scale reads 587 N; while it's slowing down, the scale reads 397 N.

Once it stops, of course, the reading will equal his normal weight.
 

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