Why Does the Scale Reading Change in an Accelerating Elevator?

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Homework Help Overview

The problem involves a woman standing on a scale in an accelerating elevator, with specific masses given for both the woman and the elevator. The scenario explores how the scale reading changes during upward acceleration, with a focus on the forces acting on the system.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculations for acceleration and the forces involved, questioning the inclusion of the woman's mass in the calculations. There is a focus on understanding how the scale reading is affected by the acceleration of the elevator.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on the importance of including the woman's mass in the calculations. There is an ongoing exploration of the calculations and interpretations of the scale readings, but no consensus has been reached on the final answer.

Contextual Notes

Participants note the requirement for the scale reading to be expressed in Newtons and discuss the implications of feeling heavier or lighter in an accelerating elevator.

keemosabi
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Homework Statement


A woman stands on a scale in a moving elevator. Her mass is 58.5 kg, and the combined mass of the elevator and scale is an additional 815 kg. Starting from rest, the elevator accelerates upward. During the acceleration, the hoisting cable applies a force of 9510 N. What does the scale read during the acceleration?


Homework Equations


Fnet = ma


The Attempt at a Solution


I found the acceleration of the entire elevator by doing 9510 - 815(9.8) = 1523. I divided this by 815 to get 1.8687. It is in the negative direction, so it is -1.8687 If this is the acceleration of the elevator, it must also be the acceleration of the person. As a result, I did Fnet = ma, Fnet = (58.5)(-1.8697) and got Fnet = 682.31895. I put 682.31895 as the what the scale reads but it says I got the answer wrong. What did I do incorrectly?
 
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How many scales have you stepped on that give a reading in Newtons? When you are in an elevator that starts going up, do you feel momentarily heavier or lighter?
 
D H said:
How many scales have you stepped on that give a reading in Newtons?
The space to fill in the answer requests that it be given in Newtons.
When you are in an elevator that starts going up, do you feel momentarily heavier or lighter?
I believe you feel momentarily heavier.
 
keemosabi said:
Her mass is 58.5 kg, and the combined mass of the elevator and scale is an additional 815 kg.

I found the acceleration of the entire elevator by doing 9510 - 815(9.8) = 1523. I divided this by 815 to get 1.8687.

What did I do incorrectly?

You forgot about the mass of the woman.
 
D H said:
You forgot about the mass of the woman.
Is that because it says that the elevator and the scale provide an additional mass?
 
Yes. That's why I highlighted the word additional.
 
Code:
9510 - 815(9.8) = 1523. I divided this by 815 to get 1.8687.

So basically just add 58.5 to each of those calculations where I used 815?
 
What does that get you?
 
D H said:
What does that get you?
It accounts for the weight of the woman in all of my calculations.
 
  • #10
So is the answer 636.8895?
 
  • #11
I get a very slightly different answer from your 636.8895 Newtons.

From your first post, it appears you are using some electronic form that tells you whether your answer is correct. Did it accept 636.8895 Newtons? If it did not accept that, show your work.
 

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