I Why is this 3D operator with degeneracies only giving me 2 eigenstates

struggling_student
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The matrix representation of a certain operator in a certain basis is

$$\begin{bmatrix} 1 & 0 & 0 \\0 & 0 & -i \\ 0 & i & 0
\end{bmatrix} .$$

The eigenvalue problem leads to this equation

$$0=det\begin{bmatrix} 1-\lambda & 0 & 0 \\0 & -\lambda & -i \\ 0 & i & -\lambda
\end{bmatrix} =-(\lambda-1)^2(\lambda+1).$$

So the eigenvalues are ##1##, ##1## and ##-1##. There is a degenacy and this means that there are two distinct states with the same eigenvalue but I would like to find all the eigenstates, generically denoted as ##\begin{bmatrix} a \\b \\ c \end{bmatrix}##.

First, the non-degenerate ##\lambda=-1## leads to the following equation

$$0=\begin{bmatrix} 2 & 0 & 0 \\0 & 1 & -i \\ 0 & i & 1 \end{bmatrix} \begin{bmatrix} a \\b \\ c \end{bmatrix},$$

$$\therefore 2a=0 \ and \ b=ic.$$

So the nondegenerate eigenstate is ##\begin{bmatrix} 0 \\ic \\ c \end{bmatrix}=\begin{bmatrix} 0 \\i \\ 1 \end{bmatrix}## because without the loss of generality we can set ##c:=1##.

Now, for the degerate ##\lambda=1## the equation is

$$0=\begin{bmatrix} 0 & 0 & 0 \\0 & -1 & -i \\ 0 & i & -1 \end{bmatrix} \begin{bmatrix} a \\b \\ c \end{bmatrix},$$

##\therefore b=-ic##, any value for ##a## will do so the degerate state is ##\begin{bmatrix} a \\-ic \\ c \end{bmatrix}##. How do I interpret this?

I expected to find two different vectors but instead I've got a two-parameter result. What is the degerate state? Is what I wrote not a valid operator? Am I mistaken in thinking that a degerate eigenvalue corresponds to exactly two distinct eigenstates?
 
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If you put in two different values for ##a## you get two linearly independent vectors.
 
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Your result makes sense. The eigenvector calculation needs to give you all the vectors in the subspace (two dimensional here) with the degenerate eigenvalue. However, if you want to have a set of orthogonal vectors, then after you pick the first value of ##a## you determine the second vector by enforcing orthogonality.
 
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