- #1
Mdhiggenz
- 324
- 1
Homework Statement
I am a bit confused on why they can just randomly short the 4kΩ resistor, as you can see from the first pic to the second pic.
THanks
Why Short the 4kΩ Resistor in Source Transformation?
- Thread starter Mdhiggenz
- Start date
Click For Summary
SUMMARY
The discussion clarifies the process of shorting a 4kΩ resistor in the context of Thevenin equivalent circuits. The 5 mA current source, along with the 16kΩ resistor and the 4kΩ resistor, is transformed into a Thevenin equivalent, allowing for simplification in circuit analysis. This transformation is essential for understanding how to analyze circuits effectively without altering the overall behavior of the circuit.
PREREQUISITES- Thevenin's Theorem
- Norton’s Theorem
- Basic circuit analysis techniques
- Understanding of resistors and current sources
- Study Thevenin and Norton equivalent circuits in detail
- Learn how to apply Thevenin’s Theorem in complex circuits
- Explore practical applications of circuit simplification techniques
- Review examples of circuit transformations in electrical engineering
Electrical engineering students, circuit designers, and anyone looking to deepen their understanding of circuit analysis and simplification techniques.
I am a bit confused on why they can just randomly short the 4kΩ resistor, as you can see from the first pic to the second pic.
THanks
- #2
barryj
- 856
- 51
They didn't just short the 4K resistor. The 5 ma current source, the 16K resistor and the 4 k resistor was made into a norton (or is it thevinin) equivalent.
- #3
barryj
- 856
- 51
It's Thevinin, I just checked.
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