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Thank you. Lucas

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- Thread starter Lucasss84
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Thank you. Lucas

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Because they are different equations! In the second equation, you can substitute [itex]y=\sqrt{x}[/itex] and it becomes [itex]y^2+ay+b=0[/itex]. Now the solution to the second equation is the same as the solution of the first, but remember that the solution we've got for the second equation is [itex]y[/itex], not [itex]x[/itex]! To find [itex]x[/itex], you have to square the solution you've got, and the solutions are different.

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HallsofIvy

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Now, what do you

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