Why use sin^2() in calculating a potential and how can you go from 3 to 5?

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The discussion centers on the use of sin^2() in potential calculations, specifically addressing a potential error in a referenced book. Participants assert that the correct mathematical expression should utilize sin(θ) instead of sin^2(θ). This clarification is crucial for accurate computations in physics or engineering contexts where potential is calculated using trigonometric functions.

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Bert
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why do the use sin^2()? en who can you go from 3 to 5.
http://img413.imageshack.us/img413/3919/verband1bismy6.jpg
http://img254.imageshack.us/img254/6993/verband2sk4.jpg

Thanks.
 
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Looks to me like a simple error in the book. Should be [itex]sin(\theta)[/itex] rather than sin squared.
 
I thinks also but I'm not certain.

Thanks.
 

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