Why Was My Answer of 63 cm for the Focal Length of a Converging Lens Incorrect?

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The focal length of a converging lens is determined using the lens formula, which relates object distance, image distance, and focal length. In this case, the object distance is 14 cm and the virtual image is located 18 cm from the object, resulting in an image distance of -4 cm (since virtual images have negative distances). Applying the lens formula (1/f = 1/do + 1/di) reveals that the correct focal length is not 63 cm. The error likely stems from miscalculating the image distance or not properly applying the lens formula. Understanding these calculations is essential for accurately determining the focal length of a lens.
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Homework Statement
An object is in a distance of 14 cm from a converging lens. The lens produces a virtual image at a distance 18 cm from the object.

What is the focal length of the lens (in cm).
Relevant Equations
1/f = 1/di + 1/do
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I attempted and keyed in the answer as 63 but I was graded wrong. What am I missing?
 
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syllll_213 said:
Homework Statement: An object is in a distance of 14 cm from a converging lens. The lens produces a virtual image at a distance 18 cm from the object.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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