Will an Aqueous Solution of KBr Be Acidic, Basic, or Neutral?

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Discussion Overview

The discussion revolves around predicting the pH of an aqueous solution of KBr, exploring whether it will be acidic, basic, or neutral. The conversation includes attempts to understand the underlying chemical reactions and the roles of the ions produced in solution.

Discussion Character

  • Homework-related
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Joanna states that the solution of KBr will be neutral but expresses confusion about the reasoning behind this conclusion.
  • Some participants question the validity of the reaction presented by Joanna, noting that it does not balance.
  • Another participant mentions that KBr is neutral because neither K+ nor Br- is acidic or basic.
  • One participant explains that Br- is the conjugate base of HBr, a strong acid, suggesting that it has a negligible effect on pH.
  • Discussion shifts to another compound, KHCO3, with participants predicting it will be basic due to the presence of OH- as a product in its dissociation.
  • It is noted that HCO3- can act as both an acid and a base, but is predominantly basic.

Areas of Agreement / Disagreement

Participants generally agree that KBr is neutral, although there is some confusion and debate about the reasoning behind this conclusion. There is also a discussion about the behavior of KHCO3, which is seen as basic, indicating a divergence in views on different compounds.

Contextual Notes

There are unresolved questions regarding the balancing of the reactions presented and the assumptions made about the behavior of the ions in solution.

Who May Find This Useful

Students studying acid-base chemistry, particularly those interested in the properties of salts and their solutions.

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Homework Statement


Predict whether an aqueous solution of KBr will be acidic, basic, or neutral.

Homework Equations


KBr(s) → K+(aq) + Br-(aq)
Br-(aq) + H2O(l) ← HBr(aq) + H3O+(aq)

The Attempt at a Solution


The solution will be neutral.

I know that this is the correct answer. I just don't know how they got there.
What I am thinking is: We first dissociate KBr, which will give us the 1st reaction, then we discard the K+ since it's a salt and doesn't affect the pH, and then we see what the reactants are going to be if we dissociate the other product (Br-) in H2O. Apparently, the products of the second reaction are supposed to tell us what the pH of the KBr solution will be.

How?
I know that HBr is a strong acid. I would have thought that the solution is acidic, not neutral. What makes it neutral?

Thank you,

Joanna.
 
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I'm a bit concerned here because (to me) it looks like your second reaction doesn't make sense... it doesn't balance at all.
 
That's the answer we got from the teacher... I don't understand it either.
 
We can try another one:

Predict whether an aqueous solution of KHCO3 will be acidic, basic, or neutral?

Reactions:

KHCO3(s) → K+(aq) + CO3-(aq)
CO3-(aq) + H2O(l) <=> HCO3(aq) + OH-(aq)

Solution:
The solution will be basic.

Explanation: Is it basic because we have OH- as a product?
 
The solution is going to be basic because KHCO3 has a basic component, HCO3-, HCO3- reacts with water

HCO3- (aq) + H2O (l) <-->H2CO3 (aq)+ OH- (aq)

bicarbonate is actually an ampholyte, it can be considered as an acid or base, however it is predominantly basic.

KBr is neutral, because neither components of KBr is acidic or basic.
 
Oh wait, I think I understand about the KBr. Tell me if my reasoning is wrong:

We get K+, which is a salt, so neither basic or acidic, and we get Br-, which is the conjugate base of HBr => since HBr is a strong acid, it's conjugate base with be very weak, and so it has no real effect on the pH...
Would that be correct?

Thanks!
 
K+ can be considered as an acid/base, but it is indeed weak with respect to both, your argument for the Br- is good.
 
Thank you!
 

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