Word problem(finding dimensions)

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Discussion Overview

The discussion revolves around solving a word problem related to finding the dimensions of a rectangular vegetable garden based on its perimeter and the relationship between its length and width. The focus is on setting up equations and solving for the dimensions, which involves mathematical reasoning and problem-solving techniques.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents the problem and seeks help in setting up an equation for the perimeter of the garden.
  • Another participant suggests using the variables for width (W) and length (L) and provides the perimeter equation: 210=2(L+W).
  • A participant expresses confusion about how to express the relationship between length and width.
  • Another participant clarifies that the length can be expressed as L=3/4W and substitutes this into the perimeter equation.
  • One participant calculates the width as W=60 and the length as L=45, confirming the values with another participant.

Areas of Agreement / Disagreement

Participants generally agree on the approach to solving the problem, with some confusion expressed initially. The final values for width and length are confirmed by multiple participants.

Contextual Notes

Some participants initially struggled with setting up the equations, indicating a potential gap in understanding how to translate the problem statement into mathematical expressions.

Who May Find This Useful

Students or individuals seeking assistance with word problems in mathematics, particularly those involving perimeter and relationships between dimensions.

pita0001
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The Children at Tiny Tots Day Care plant a rectangular vegetable garden with a perimeter of 210m. The length is 3/4 the width, Find the dimensions of the garden.

I have no idea how to set up an equation. Any help is appreciated.

Would it be like 210=2(3/4+x)?

or 210=2(x-.25)?
 
Last edited:
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You are close. Let's let $W$ be the width and $L$ be the length, and so the perimeter is:

$$210=2(L+W)$$

Now, if the length is 3/4 the width, how can we rewrite $L$ in terms of $W$?
 
I don't know:confused::confused:

210=2(L-3/4)

or 210=2(L*3/4)?
 
The statement "The length is 3/4 the width" translates into an equation as follows:

$$L=\frac{3}{4}W$$

So, substituting that into the first equation, we obtain:

$$210=2\left(\frac{3}{4}W+W \right)$$

So, now you want to solve this equation for $W$, and then use the relationship above between $L$ and $W$ to obtain the value of $L$. What do you find?
 
I get 210=1.5w+2w
so W=60?
and length 45
 
pita0001 said:
I get 210=1.5w+2w
so W=60?

Yes that's correct, and so if $L$ is 3/4 of that value, what is the length?
 
Length=45

thanks!:)
 

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