- #1

karush

Gold Member

MHB

- 3,267

- 4

$\tiny{\textbf{2.4.10}}$

$\begin{array}{rl}

(x+4)^2+(y+11)^2&=169 \\

(x-9)^2+(y+5)^2&=100 \\

(x-4)^2+(y-5)^2&=25

\end{array}$

ok i solved this by a lot of steps and got (1,1) as the intersection of all 3 circles

these has got to be other options to this.

basically I expanded the equations then set them equal to each other but what a mess:unsure:

suggestions?

I was thinking about a matrix but not sure how to set it up

[DESMOS]{"version":7,"graph":{"viewport":{"xmin":-10,"ymin":-11.610693119544644,"xmax":10,"ymax":11.610693119544644}},"randomSeed":"ae14e0f6a73aec6ad68af003f395e465","expressions":{"list":[{"type":"expression","id":"1","color":"#c74440","latex":"(x+4)^{2}+(y+11)^{2}=169"},{"type":"expression","id":"2","color":"#2d70b3","latex":"(x-9)^{2}+(y+5)^{2}=100"},{"type":"expression","id":"3","color":"#388c46","latex":"(x-4)^{2}+(y-5)^{2}=25"},{"type":"expression","id":"4","color":"#6042a6","latex":"\\left(1,1\\right)","showLabel":true}]}}[/DESMOS]

$\begin{array}{rl}

(x+4)^2+(y+11)^2&=169 \\

(x-9)^2+(y+5)^2&=100 \\

(x-4)^2+(y-5)^2&=25

\end{array}$

ok i solved this by a lot of steps and got (1,1) as the intersection of all 3 circles

these has got to be other options to this.

basically I expanded the equations then set them equal to each other but what a mess:unsure:

suggestions?

I was thinking about a matrix but not sure how to set it up

[DESMOS]{"version":7,"graph":{"viewport":{"xmin":-10,"ymin":-11.610693119544644,"xmax":10,"ymax":11.610693119544644}},"randomSeed":"ae14e0f6a73aec6ad68af003f395e465","expressions":{"list":[{"type":"expression","id":"1","color":"#c74440","latex":"(x+4)^{2}+(y+11)^{2}=169"},{"type":"expression","id":"2","color":"#2d70b3","latex":"(x-9)^{2}+(y+5)^{2}=100"},{"type":"expression","id":"3","color":"#388c46","latex":"(x-4)^{2}+(y-5)^{2}=25"},{"type":"expression","id":"4","color":"#6042a6","latex":"\\left(1,1\\right)","showLabel":true}]}}[/DESMOS]

Last edited: