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## Homework Statement

The following is the data I collected. I set a weight on a spring and measured how far the spring was stretched. The spring was not oscillating, just stretched and left at rest.

Load (kg):

0.300

0.400

0.500

0.600

0.700

0.800

0.900

Weight (Converted the above load in to N):

2.94

3.92

4.90

5.88

6.86

7.85

8.83

5.39

6.37

Stretch (m):

0.059

0.076

0.095

0.115

0.134

0.154

0.174

0.105

0.125

The question is, how do I find the work from the above and how do I find the elastic potential energy.

## Homework Equations

(1/2)kx^2

## The Attempt at a Solution

[tex]Work = Fd[/tex]

[tex]W = (2.94)(0.059) = 0.17346[/tex]

[tex]F = kx[/tex]

[tex]k = F/x[/tex]

[tex]2.94 / 0.059 = 49.8[/tex]

[tex]U_{elastic} = \frac{1}{2}kx^2[/tex]

[tex]U_{elastic} = \frac{1}{2}(49.8)(0.059^2) = 0.08673[/tex]

I'm pretty sure I did something wrong. It also asks me to compare the work done and the elastic potential energy. I thought W = Ue in this case, but the calculations show differently. But I think the calculations are wrong. Any help would be greatly appreciated.