(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A single force acts on a 5.0 kg particle-like object in such a way that the position of the object as a function of time is given by x = 3.0t - 4.0t^2 + 1.0t^3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 2.0 s.

2. Relevant equations

x=3.0t-4.0t^2+1t^3

W=Fd

W=integral(Fdx)

3. The attempt at a solution

So when t=0, x=0.

When t=2, x=-2

displacement= -2-0 = -2m

W=Fd

F=ma=(5)(9.8)=49

W=(49 N)(-2 m)

W= -98 J

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Work done on the object problem

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