Work-Energy Method: Solving Doubled Initial Speed of Car

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Homework Help Overview

The problem involves a car being stopped by a constant friction force, with a focus on how the stopping distance changes when the car's initial speed is doubled. The context is within the work-energy method in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between stopping distance and kinetic energy, with some exploring the implications of increased initial speed on stopping distance. Questions are raised about the factors affecting stopping distance and the relevant equations.

Discussion Status

The discussion is ongoing, with participants providing insights into the relationship between work, force, and stopping distance. Some guidance has been offered regarding the equations involved, but multiple interpretations and questions remain without a clear consensus.

Contextual Notes

Participants are considering the implications of varying initial speeds and the nature of the friction force, which is stated to be independent of speed. There is also a mention of a specific answer related to a tripled speed, indicating a need for further clarification on the underlying principles.

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[SOLVED] Work-Energy Method

Homework Statement



A car is stopped by a constant friction force that is independent of the car's speed. By what factor is the stopping distance changed if the car's initial speed is doubled? (Solve using work-energy methods.)

Homework Equations



Wtotal = delta K

The Attempt at a Solution



From what the problem is stating, is that friction force, is separate from car's speed.
''if the car's initial speed is doubled?''
K1 = 1/2(m)(2v)^2

I know the answer is 4, but I don't comprehend, what is the car's initial speed is tripled, would it be 6?
 
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How does stopping distance relate to kinetic energy?
 
well if the velocity is higher, then it would be harder to stop at a shorter distance than a long one.
 
I'm looking for a precise answer. What factors affect stopping distance? Give an equation.
 
well

W = F*s

s being distance

and work total = k2-k1

so, k2-k1 = F*s
 

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