Work Energy Problem: Calculating Distance with Friction

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SUMMARY

In the work energy problem presented, Juana pushes a crate with a mass of 59.1 kg using a force of 111 N while overcoming a coefficient of kinetic friction of 0.120. The total work done on the crate is 73.3 J. To calculate the distance the crate moves along the van floor, the work-energy principle is applied, specifically using the equation w = f * d, where 'w' is work, 'f' is the net force acting on the crate, and 'd' is the distance. The confusion regarding static friction is clarified, emphasizing that only kinetic friction is relevant in this scenario.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the work-energy principle
  • Knowledge of kinetic friction and its calculation
  • Basic algebra for solving equations
NEXT STEPS
  • Study the work-energy theorem in detail
  • Learn how to calculate net force considering friction
  • Explore examples of work done against friction in various scenarios
  • Review the differences between static and kinetic friction
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the application of work-energy principles in real-world scenarios involving friction.

Jtappan
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Homework Statement



Juana slides a crate along the floor of the moving van. The coefficient of kinetic friction between the crate and the van floor is 0.120. The crate has a mass of 59.1 kg and Juana pushes with a horizontal force of 111 N. If 73.3 J of total work are done on the crate, how far along the van floor does it move?

____J

Homework Equations



w=fd?

The Attempt at a Solution



How does static friction fit into this equation? I know this is a work problem but I am just confused as to how I put static friction into the equation.
 
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Its kinetic friction, not static since the crate is moving. You misread the question.
 

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