(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A box of 2Kg is projected with a speed of 6m/s up a slope at 30* to horizontal. The coeffiecient of friction is 1/3. Use the work energy principle tp calculate the distance travelled by the box before coming to rest.

2. Relevant equations

When you calculate the work done against friction, why don't you take into account the 2gsin30 force acting downwards and only use Fmax? Surely the force acting on the box is both?

3. The attempt at a solution

KE lost = 0.5 x 2 x 36 = 36J

PE gained = 2 x 9.8 x dsin30 = 9.8d

Work done against friction = Fd = (2gsin30 + 1/3 x 2gcos30) x d= 15.46d

Work done = total loss of energy

15.46d = 36 - 9.8d

d=1.43m

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# Homework Help: Work-energy problems on a slope

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