Work-Kinetic Energy Theorum Problem

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Homework Help Overview

The problem involves a car descending a sloped driveway, where the effects of friction and gravitational forces on the car's motion are being analyzed. The context is rooted in the work-kinetic energy theorem.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to apply the work-kinetic energy theorem but expresses confusion regarding the role of friction and the need to account for gravitational potential energy. Some participants suggest considering gravitational forces and their impact on the energy transformation involved.

Discussion Status

Participants are exploring the implications of gravitational potential energy in the context of the problem. There is a recognition that the original poster's approach may be incomplete without considering the work done by gravity. Suggestions have been made to visualize the forces acting on the car through a free body diagram.

Contextual Notes

The original poster notes that the section of the text being referenced does not cover gravitational potential energy, which raises questions about the assumptions being made regarding the problem's constraints.

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Homework Statement



A 2.1 x 10^3 kg car starts from rest at the top of a driveway that's sloped at an angle of 20.0 degrees with the horizontal. An avg. friction force of 4.0 x 10^3 impedes the cars motion so that the cars speed at the bottom of the driveway is 3.8m/s. What is the length of the driveway?


Homework Equations


Wnet = change in KE
KE=1/2mv^2
(so you can substitute it)
Wnet = Fdcos(angle)



The Attempt at a Solution



I'm racking my brain here! I don't know what I'm doing wrong...

Wnet = (Fnet)(d)(cos angle)
Wnet = change in KE
Wnet = (KE f) - (KE i)
Wnet = KEf - 0
Wnet = 1/2mvf^2

*****note mvf is mass(final velocity)^2*****

1/2mvf^2 = Fdcos(angle)
1/2(2.1 x 10^3)(14.44) = 4.0 x 10^3(cos 20) (d)
15,162 = 3758.77d
d=4.03 m

**The book's answer is 5.1 m

Now, I'm not sure how to handle the fact that friction is acting in the opposite direction that the work is being done, so i don't know how to account for that negative work, since the answer is not negative.

But other than that, i don't know how to get 5.1

Any help is appreciated!
 
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The car starts from the top of a slope... that means there's some gravitational potential energy you haven't included.
 
physics girl phd said:
The car starts from the top of a slope... that means there's some gravitational potential energy you haven't included.

That can't be though...I wrote everything the problem said. Plus, this section does not cover grav. potential energy, so it cannot be in the problem (the next section talks about it).
 
Regardless of where it's discussed in your text, you have to include the effect of the gravitational force, which is doing work on the object to change some of the energy of the object from potential energy to kinetic energy.

If you decide to treat it as a force... draw a free body diagram of the object on a slope. there should be three forces, the gravitational force, the friction force, and the support force of the slope (the normal force).

1) Gravitational force does work on the object to put energy in (in a certain manner dependent on the slope)... let's call that POSITIVE work.
2) The friction force takes energy away from the object (NEGATIVE work).
3) The final energy of the object (it's kinetic energy) is the positive work done on the object minus the negative work.

Thats a way of doing it without the definition of gravitational potential energy.
 

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