Work to create a square of charges

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SUMMARY

The discussion focuses on calculating the work required to create a square configuration of charges, specifically with charges +q and -q positioned at the corners of a square with side length 'a'. The work is derived from the change in potential energy, expressed as U = kqq/r, where 'k' is Coulomb's constant. The initial work for the first charge is zero, while the subsequent charges require calculations based on their distances from existing charges. The final expression for the work needed to bring the last charge can be inferred from the previous calculations.

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  • Familiarity with potential energy equations in electrostatics
  • Knowledge of charge configurations and their interactions
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supersunshine
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hi,
i'm completely stuck on this problem

Homework Statement


the problem asks for an expression for the work required to create a square charge configuration starting with the charges starting at infinity:
each side is length a. on the top left corner the charge is +q, top right: -q, bottom left: -q, bottom right +q

Homework Equations


change in potential energy= work
U= kqq/r

The Attempt at a Solution


Since the charges begin at infinity, the work will equal the final potential energy. I think potential energies can be added, but if you add all the charges at equal distances you will get zero. I also tried chosing a corner and adding the potential energies relative to the corners but did not get the right answer.

thank you for your help!
 
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supersunshine said:
hi,
i'm completely stuck on this problem

Homework Statement


the problem asks for an expression for the work required to create a square charge configuration starting with the charges starting at infinity:
each side is length a. on the top left corner the charge is +q, top right: -q, bottom left: -q, bottom right +q

Homework Equations


change in potential energy= work
U= kqq/r

The Attempt at a Solution


Since the charges begin at infinity, the work will equal the final potential energy. I think potential energies can be added, but if you add all the charges at equal distances you will get zero. I also tried chosing a corner and adding the potential energies relative to the corners but did not get the right answer.

thank you for your help!

The work required to bring the first charge is zero.
The work required to bring the second charge will be [itex]\frac{k q_1 q_2}{r_{12}}[/itex] where r_12 is the distance between those two charges at the final position. The work required to bring the third charge is [itex]\frac{k q_1 q_3}{r_{13}} +\frac{k q_2 q_3}{r_{23}}[/itex] since q_2 and q_3 are already there. You can guess the formula for the work to bring the last charge :-p !

Hope this helps
 

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