Working With A Rectangular Garden

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The discussion focuses on calculating the perimeter of a rectangular garden with dimensions 15 meters by 10 meters, surrounded by a walkway of width x. The correct equation for the perimeter of the walkway is derived as y = 4x + 50, accounting for both the inner and outer dimensions. There is a need for a clear diagram to represent the problem accurately, as previous attempts were deemed incorrect. Participants emphasize the importance of distinguishing between the inner perimeter of the garden and the outer perimeter of the walkway. Clarification on the dimensions and layout is necessary for a complete understanding of the problem.
nycmathguy
Homework Statement
1. Draw a diagram representing the problem.
2. Write equation representing the perimeter.
Relevant Equations
P = 2L + 2W
The length and width of a rectangular garden are 15 meters and 10 meters, respectively. A walkway of width x surrounds the garden.

(a) Draw a diagram that gives a visual representation of the problem.

(b) Write the equation for the perimeter y of the walkway in terms of x.

For (a), see attachment.

For (b):

y = 2L + 2W

y = 2(x + 15) + 2(x + 10)

y = 2x + 30 + 2x + 20

y = 4x + 50

Is any of this right?
 

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nycmathguy said:
Homework Statement:: 1. Draw a diagram representing the problem.
2. Write equation representing the perimeter.
Relevant Equations:: P = 2L + 2W

y = 2(x + 15) + 2(x + 10)
y=2(2x+15)+2(2x+10)
 

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anuttarasammyak said:
y=2(2x+15)+2(2x+10)
I was right the first time but doubted my work.
 
nycmathguy said:
A walkway of width x surrounds the garden.
(a) Draw a diagram that gives a visual representation of the problem.

nycmathguy said:
I was right the first time but doubted my work.
Your diagram, which is part a, is incorrect. The work for part b, but it doesn't align with your drawing. You have x being the length of the short side of the outer rectangle. Per the problem statement, x is the width of the walkway.
 
I think we should discriminate between the outer and the inner perimeter of the walkway.
The outer perimeter of the walkway is 2(2x+15)+2(2x+10).
The inner perimeter of the walkway is equal to the perimeter of the garden, that is 2*15+2*10.
 
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Mark44 said:
Your diagram, which is part a, is incorrect. The work for part b, but it doesn't align with your drawing. You have x being the length of the short side of the outer rectangle. Per the problem statement, x is the width of the walkway.
Can you draw the right figure for me?
 
nycmathguy said:
Can you draw the right figure for me?
Come on... you can do it. The garden is 15 by 10, and there is a walkway around the garden that is x feet wide.
 
Mark44 said:
Come on... you can do it. The garden is 15 by 10, and there is a walkway around the garden that is x feet wide.
See attachment.
 

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