Event Horizon of Telescope Through Earth: Does It Exist?

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SUMMARY

The discussion centers on the theoretical implications of using a telescope drilled through the Earth to observe stars on the opposite side. Answer #1 asserts that the telescope's visibility is limited by an event horizon due to constant gravitational acceleration of 1g, suggesting that stars beyond approximately one light year cannot be seen. Conversely, Answer #2 argues that the telescope's position relative to the stars remains unchanged, allowing visibility of distant stars, thus challenging the applicability of Einstein's equivalence principle in this scenario. Ultimately, the consensus favors Answer #2, emphasizing the non-local nature of the observations and the inapplicability of the equivalence principle in this context.

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Tantal
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Assume we drill a hole through the Earth - through the center towards the other side. Then we use a telescope, point it through the hole and observe stars on the other side of the earth. The telescope experiences a constant acceleration from Earth's gravitation. Accelerated movements have an event horizon. Is the sight of our telescope limited by this horizon?

Answer #1: Yes. The telescope experiences a constant acceleration of 1g, so any star beyond the distance d=c^2/9.81 (~ one light year) is not visible. Furthermore, Einstein's equivalence principle (the comparison with an accelerated rocket) favors this answer.

Answer #2: No. The position of the telescope relatively to the stars does not change. It is the same as for any other position on Earth's surface, so Earth's gravitational accelaration does not matter. Furthermore, there would be no problem for another telescope on the far end of the hole in observing faraway stars. The photons of such stars which made it up to the far end telescope should have no troubles to pass the rest of their journey through the hole - like photons of a flash light positioned at the far end of the hole.

Because of the flash light argument Answer #2 seems to be the only choice. But then Einstein's equivalence would not hold. Where is the flaw in these answers?
 
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Tantal said:
Because of the flash light argument Answer #2 seems to be the only choice.

Yes, answer #2 is correct. Answer #1 would be correct if spacetime were flat, but it isn't.

Tantal said:
But then Einstein's equivalence would not hold.

The observations you are talking about are not local; they are not confined to a small enough region of spacetime that tidal gravity is negligible. So the EP does not apply, and the observations you describe do not mean the EP does not hold.
 

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